Solution of C Programming by E Balaguruswamy

CHAPTER-1 Problem exercise no 1.1&1.2: Coding of the programme: #include #include void main() { clrscr(); printf("---------------------------------------\n"); printf("I First line :A.Z.M.Shakilur Rahman I\nI Second line :12/a ,Ali sonar lane I\nI Third line:Bogra,5800 I\n"); printf("---------------------------------------"); getch(); }

Output:

Problem exercise no. 1.3: Coding of the programme: #include #include void main() {clrscr(); printf("*\n* *\n* * *\n* * * * "); getch(); } Output: * ** *** ****

Problem exercise no :1.4 Coding of the problem: #include #include void main() {clrscr(); printf("a>>------------------>b"); getch(); }

Output: a>>------------------>b

Problem exercise no:1.5 Coding of the problem: #include

#include #define pi 3.14159 void main() { float r,A; clrscr(); printf("\n\tENTER THE RADIUS OF A CIRCLE="); scanf("%f",&r); A=pi*r*r; printf("\n\n\tArea=%f sqr unit",A); getch(); }

Output: ENTER THE RADIUS OF A CIRCLE=2 Area=12.566360 sqr unit

Problem exercise no:1.6 CODING: #include #include void main() { int b,c; clrscr(); for(b=1;b<=10;b++) { c=5*b; printf("\n\t%d*%d=%d\n",5,b,c); getch(); } } Output :

Problem exercise no:1.7 Coding of the programme: #include #include void add(); void sub(); void main() { clrscr(); add(); sub(); getch(); } void add() { printf("\n\t%d+%d=%d",20,10,30); }

void sub() { printf("\n\t%d-%d=%d",20,10,10); }

Output : 20+10=30 20-10=10

Problem exercise no:1.8 Coding: #include #include void main() { int a,b,c,x; clrscr(); printf("Enter values of a,b&c\n"); scanf("%d%d%d",&a,&b,&c); x=a/(b-c); printf("result=%d",x); getch(); }

Output: a) Enter values of a,b&c 250 85 25 result=4 b)NO OUTPUT

Problem exercise no:1.9 (b) Coding : #include #include void main() { float a,F,C; clrscr(); printf("ENTER TEMPERATURE IN FARENHITE\n"); scanf("%f",&F); a=5*(F-32); C=a/9; printf("\nIn celsius scale=%f",C); getch(); }

Output : ENTER TEMPERATURE IN FARENHITE 10 In Celsius scale=-12.222222

Problem exercise no:1.9 (a)

Coding : #include #include void main() { float a,F,C; clrscr(); printf("ENTER TEMPERATURE IN CELSIUS\n"); scanf("%f",&C); a=(9*C)/5; F=a+32; printf("\nIn farenhite scale=%f",F); getch(); } Output: ENTER TEMPERATURE IN CELSIUS 10 In frenhite scale=50.00000

Problem exercise no: 1.10 Coding of the problem: #include #include #include void main() { clrscr(); float a,b,c,S,A; printf("\n\tENTER THE THREE SIDES OF A TRIANGLE="); scanf("%f%f%f",&a,&b,&c); S=(a+b+c)/2; A=sqrt(S*(S-a)*(S-b)*(S-c)); printf("\n\tArea of the triangle=%f",A); getch(); }

Sample output: ENTER THE THREE SIDES OF A TRIANGLE=10 12 14 Area of the triangle=58.787754

Problem exercise no:1.11 Coding: #include #include #include void main() { float D,x1,x2,y1,y2; clrscr();

printf("ENTER CO-ORDINATES x1,x2,y1,y2=\n"); scanf("%f%f%f%f",&x1,&x2,&y1,&y2); D=sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); printf("Result=%f",D); getch(); }

Output : ENTER CO-ORDINATES x1,x2,y1,y2= 2 4 8 5 Result=3.605551

Problem exercise no:1.12 Coding: #include #include #include #define pi 3.14159 void main() { float r,x1,x2,y1,y2,A; clrscr(); x1=0; x2=0; y1=4; y2=5; r=sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); A=pi*r*r; printf("Result=%f",A); getch(); }

Output : Result=3.14159

Problem exercise no:1.13 Coding: #include #include #include #define pi 3.14159 void main() { float D,r,x1,x2,y1,y2,A; clrscr(); x1=2; x2=2; y1=5; y2=6; D=sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); r=D/2;

A=pi*r*r; printf("Result=%f",A); getch(); }

Output : Result=0.785398

Problem exercise no:1.14 Coding: #include #include void main() { int a,b,c; clrscr(); a=5; b=8; c=18; printf("%dx+%dy=%d",a,b,c); getch(); }

Output : 5x+8y=18

Problem exercise no:1.15 Coding: #include #include void main() { float x,y,sum,difference,product,division; clrscr(); printf("ENTER TWO NUMBERS=\n"); scanf("%f%f",&x,&y); sum=x+y; difference=x-y; product=x*y; division=x/y; printf("\n\tSum=%f\tDifference=%f\n\n\tProduct=%f\tDivision= %f",sum,difference,product,division); getch(); }

Output : ENTER TWO NUMBERS= 10 5 Sum=15.000000

Difference=5.000000

Product=50.000000

Division=2.000000

solution of C programming by E.Balagurusamy CHAPTER-2

CHAPTER 2 Constants, Variables, and Data Types REVIEW QUESTIONS STATE WHETHER THE FOLLOWING STATEMENTS ARE TRUE OR FALSE: (a) Any valid printable ANSII character can be used in an identifier. ( False ) (b) All variables must be given a type when they are declared. ( True ) (c) Declarations can appear anywhere in a program. ( False ) (d) ANSI C treats the variable name and Name to be same. ( False ) (e) The underscore can be used anywhere in an identifier. ( True ) (f) The keyword void is a data type in C. ( True ) (g) Floating point data constants, by default, denote float type values. ( False ) (h) Like variables, constants have a type. ( True ) (i) Character constants are coded using double quotes. (False ) (j) Initialization is the process of assigning a value to a variable at the time of declaration. ( true ) (k) All static variables are automatically initialized to zero. ( True ) (l) The scanf function can be used to read only one value at a time. ( False )

Fill in the blanks with appropriate words: (a)The keyword ……………..can be used to create a data type identifier. Answer: int (b) …………… is the largest value that an unsigned short int type variable can store. Answer: 255

(c) A global variable is also known as …………….variable. Answer: external

(d) A variable can be made constant by declaring it with the qualifier ……………. At the time of initialization. Answer: constant

Question: What are trigraph characters? How are they useful? Answer: Trigraph characters is one kinds of character which consists of three characters ( Two question marks and followed by another ). Some keyboard does not support some characters. But we can use them by trigraph characters. If a keyboard does not support square brackets, we can still use them in a program using the trigraph ??( and ??) .

Question: Describe the four basic data types. How could we extend the range of values they represent? Answer: The basic four data types are: (1) Char (2) Int (3) Float (4) Void

We cannot extend the range of character.

We could extend the range of integer by using long beforeinteger. We can extend the range of float by using double. To extend the precision further we may use long double.

Question: What is an unsigned integer constant? What is the significant of declaring a constant unsigned? Answer: The integer constant which does not take any + or – sign before it is called an unsigned integer constant. We can take the value double using an unsigned integer constant. For example, a signed integer constant have a value between -32768 to +32767, but an unsigned integer constant takes the value between 0 to 65535.

Question: Describe the characteristics and purpose of escape sequence characters. Answer: C supports some special back slash character constants, that are used in output function. This characters are known as escape sequence characters. For example, the symbol “\n” stands for new line character. Characteristics : (1) They acts as a single character. (2) Each escape sequence character consists of two characters. (3) The first character must be a back slash .

Purpose: (1) In a program we used it for new line. (2)In a program we used it for horizontal tab.

Question: What is a variable and what is meant by “value” of a variable? Answer: A variable is a data name that may used to store a data value. Like constants that remains unchanged during the execution a program. The meant of value it is a variable name and it can take any value like character, int, float and double.

Question: How do variables and symbolic names differ? Answer: A variable may be used to store data value. A variable may take different values at different times during execution of a program. Variables has need to declare at the beginning of the body but after the main. Symbolic names is a unique constants. This constants may appear in a number of place in the program. Symbolic names has need to define at the beginning of a program.

Question: State the difference between the declaration of a variable and the definition of a symbolic name? Answer: Variables has need to declare at the beginning of the body but after the main. The syntax for declaring a variable is as follow: Data-type v1,v2,……..vn; v1, v2,……..vn are the names of variables. For example, valid declarations are int count; int number,total; float ratio; Symbolic names has need to define at the beginning of a program. A symbolic name constants is defined as follows: #define symbolic-name value of constant Valid example of constant definations are: #define STRENGTH 100 #define PASS MARK 5

Question: What is initialization? Why it is important? Answer: The process of giving initial values to variables is called initialization. Some examples are

int final_value =100; char yes

=’x’;

double balance =75.84; C permits the initialization of more then one variable using multiple assignment operators.For example the statements p=q=s=0; x=y=z=MAX; are valid.

Question: What are the qualifiers that an int can have at a time? Answer: A signed int can take a value between -32768 to 32767 and an unsigned int can take a value 0 to 65535.

Question: Describe the purpose of the qualifiers constant and volatile. Answer: We may like the value of certain variables to remain constant during the excution of a program. We can achieve this by declaring the variable with the qualifier constant at the time of initialization. Example: const int class_size=40; ANSI standard defines another qualifier volatile that could be used to tell explicitly the complier that a variables value may be changed at any time by some external sources ( from outside the program). For example: volatile int date;

Question: When dealing with very small or very large numbers, what steps would you like you take to improve the accurancy of the calculation? Answer:

When we are dealing with a very short number we can improve the accurancy of calculation by using a keyword short before the keyword. Example short int. When we are dealing with a very large number we can improve the accurancy of calculation by using a keyword long before the keyword. Example long int.

Question: Which of the following are invalid constants and why? 0.0001 Answer: (valid) 5x1.5 Answer: (Invalid) Reason: Exponent must be an integer. 99999 Answer: Valid Reason: Long integer.

+100 Answer: ( valid) 75.45E-2 Answer: ( Valid ) -45.6 Answer: ( Valid ) “15.75” Answer: ( Invalid ) Reason: “” sign is not permitted.

-1.79e+4 Answer: (valid) 0.00001234 Answer: ( Valid )

Question: Which of the following are invalid variable and why? Minimum Answer: ( valid ) First.name Answer: ( Invalid ) Reason:. Sign is not permitted. N1+n2 Answer: ( Invalid ) Reason: + sign is not permitted. &name Answer: ( Invalid ) Reason: & is not permitted. Doubles Answer: ( Valid ) Reason: Keyword may be a part of variable name. 3rd_row Answer: ( Invalid ) Reason: First character must be a letter or underscore. n$ Answer: ( Invalid ) Reason: Dollar sign is not permitted. Row1 ( Valid ) Float Answer: ( Invalid ) Reason: float is a keyword. Sum Total Answer: ( Invalid ) Reason: White space is not permitted.

Row Total Answer: ( Invalid ) Reason: White space is not permitted. Column total Answer: ( Invalid ) Reason: White space is not permitted.

Question: Find errors, if any, in the following declaration statements. { Intx; float letter,DIGIT; double=p,q; exponent alpha,beta; m,n.z:INTEGER short char c; long int m;count; long float temp; getch(); } Error1: intx should have a type. Error2: Line number 6, expression syntax. Error3: Line number 7, Declaration should be properly. Error4:Line number 9, Unreachable code.

Problem no 2.1: Write a program to determine and print the sum of the following harmonic series for a given value of n: 1+1/2+1/3+………………+1/n Solve:

#include #include Void main() { int n; float I, sum, t; clrscr(); printf(“1+1/2+1/3+……………+1/n\n”); printf(“Enter the value of n\n”); scanf(“%d”,&n); sum=0; for(i=1;i<=n;i++) { t=1/i; sum=sum+t; } printf(“%f”,sum); getch(); }

Output: 1+1/2+1/3+………….+1/n Enter the value of n 4 2.083333

The value of n should be given interactively through the terminal. Problem no 2.2: Write a program to read the price of an item in decimal form ( like 15.95 ) and print the output in paisa ( like 1595 paisa) .

Solve: #include #include void main() { int b; float a; a=15.95; clrscr(); b=100*a; printf("%d",b); getch(); }

Output: 1595

Problem no 2.3: Write a program that’s prints the even numbers from 1 to 100. #include #include void main() { int i; for(i=1;i<=100;i++) { if(i%2==0) printf(" %d",i); } getch();

}

Output 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86 88 90 92 94 96 9 8 100

Problem no 2.4: Write a program that request two float type numbers from the users and then divides the first number by the second and display the result along with the numbers. Solve: #include #include void main() { float number1, number2, number3; clrscr(); printf("Enter the value of number1 and number2\n"); scanf("%f %f",&number1,&number2); number3=number1/number2; printf("%f/%f=%f",number1,number2,number3); getch();

Output: Enter the value of number1 and number2 15.5 6.6 15.5/6,6=2.348484

Problem no 2.5: The price of one kg of rice is Rs. 16.75 and one kg of sugar is Rs. 15. Write a program to get these values from the user and display the prices as follows:

***LIST OF ITEMS***

Item

Price

Rice

Rs 16.75

Sugar

Rs 15.00

Solve: #include #include void main () { float Rice,Sugar; Rice=16.75; Sugar=15.00; clrscr(); printf("***LIST OF ITEMS***\n"); printf("Item \tPrice\n"); printf("Rice\tRs%.2f\n",Rice); printf("Sugar\tRs%.2f\n",Sugar); getch(); }

Output: ***LIST OF ITEMS*** Item

Price

Rice

Rs16.75

Question: Identify syntax errors in the following program. After correcting, what output would you expect when you execute it. #include #include #define PI 3.14159 void main()

{ int R,C; float perimeter; float area; C=PI; R=5; perimeter=2.0*C*R; Area = C*R*R; printf("%f", "%d",&perimeter,&area) }

Errors: Cpp 10: Undefined symbol Area. Cpp 12:statement missing,in function{} Cpp12: compound statement missing. Solve: #include #include #define PI 3.14159 void main() { int R,C; float perimeter,Area;

C=PI; R=5; perimeter=2.0*C*R; Area = C*R*R; printf("%f %f",perimeter,Area); getch();

}

CHAPTER-3 EXERCISE NO.3.1: Given the values of the variables X,Y and Z write a program to rotate their values such that X has the value of Y,Y has the value of Z and Z has the value of X. SOLUTION: #include #include void main() { int x,y,z,temp; clrscr(); printf("Enter the value of x,y,z\n"); scanf("%d %d %d",&x,&y,&z); temp=x; x=y; y=z; z=temp; printf("%d %d %d",x,y,z); getch(); }

EXERCISE NO.3.2: write a program that reads a floating-point number and then displays right-most digit of the integral part of the number. SOLUTION: #include #include void main()

{ int a,e; float p; clrscr(); printf("Enter the value of p\n"); scanf("%f",&p); a=int(p); printf("%d\n",a); e=a%10; if(a>10) printf("%d\n",e);

getch(); } EXERCISE NO.3.3. Modify the above program to display to right-most digits of the integral part of the number. SOLUTION: #include #include void main() { int a,e; clrscr(); printf("Enter the value of a\n"); scanf("%d",&a); e=a%100;

if(a>100) printf("%d\n%d\n",a,e);

getch(); }

3.4: Write a program that will obtain the length and width of a rectangle from the user and compute its area and perimeter. SOLUTION: #include #include void main() {

int length,width; clrscr(); float area,perimeter; printf("Enter the value of length,width\n"); scanf("%d %d",&length,&width); area=(length*width); perimeter=2*(length+width); printf("%f %f",area,perimeter); getch(); }

EXERCISE NO.3.5: Given an integer number, write a program that displays the number as follows: First line: all digits Second line: all except first digit Third line: all except first two digits

………… Last line: The last digit For example the number 5678 will be displayed as: 5678 678 8 SOLUTION: #include #include void main() { int a,b,c,e,x; float p; clrscr(); printf("Enter the value of p\n"); scanf("%f",&p); a=int(p); printf("%d\n",a); e=a%10000; b=e%1000; c=b%100; x=c%10; if(a>10000) printf("%d\n%d\n%d\n%d\n",a,e,b,c,x); else if(a>1000) printf("%d\n%d\n%d\n",a,b,c,x); else if(a>100) printf("%d\n%d\n",a,c,x); else if(a>10)

printf("%d\n%d\n",a,x);

getch(); }

EXERCISE NO.3.6: The straight-line method of computing the yearly depreciation of the value of an item is given by Depreciation=

Write a program to determine the salvage value of an item when the purchase price , years of service, and the annual depreciation are given. SOLUTION:

#include #include void main() { int years; float s, d,p; clrscr(); printf("Enter the value of years,d,p\n"); scanf("%d %f %f",&years,&d,&p); s=p-(years*d); printf("%f",s); getch(); }

EXERCISE NO.3.7: Write the program that will read a real number from the keyboard and print the following output in one line:

Smallest integer

The given

not less then

number

the number

Largest integer not greater than the number

SOLUTION:

#include #include void main() { float m; int n,p; clrscr(); printf("Enter the value of m\n"); scanf("%f",&m); n=(m/1)+1; p=m; printf("%d %f %d",n,m,p); getch(); }

EXERCISE NO.3.8: The total distance travelled by a vehicle in t seconds is given by Distance= ut+(at2)/2 Where u is the initial velocity( meter per second),a is the acceleration (meter per second2). Write a program to evaluate the distance travelled at intrevales of time, give the value of u and a. the program should provide the flexibility to the user to select his own time intervals and repeat the calculation for different value of u and a.

SOLUTION: #include void main()

{ int a,u,t; float distance; clrscr(); printf("Enter the value of a,u,t\n"); scanf("%d %d %d",&a,&u,&t); distance=u*t+(a*t*t)/2; printf("%f",distance); getch(); }

EXERCISE NO.3.9: In inventory management ,the Economic Order Quantity for a single item is given by EOQ=sqrt { ( 2*demand rate*setup rate ) / ( holding cost per item per unit time ) }

And the Time Between Orders

TBO =sqrt { ( 2* setup cost ) / (demand rate * holding cost per item per unit time ) }

SOLUTION 1: #include #include #include void main() { float EOQ,d,s,h,x; Clrscr(); printf("Enter the value of d,s,h\n"); scanf("%f %f %f",&d,&s,&h); x=(2*d*s)/h;

EOQ=sqrt(x); printf("%f",EOQ); getch(); } SOLUTION 2:

#include #include #include void main() { float x,s,d,h,TOB; clrscr(); printf("Enter the value of s,d,h\n"); scanf("%f%f%f",&s,&d,&h); x=(2*s)/(d*h); TOB=sqrt(x); printf("%f",TOB); getch(); }

EXERCISE NO.3.10: For a certain electrical circuit with an inductance L and resistance R,the damped natural frequency is given by

Frequency =sqrt { (1/L*C ) - ( R*R/4*C*C ) } It is desired to study the variation of this frequency with C(capacitance).Write a program to calculate the frequency for different values of C starting from 0.01 to 0.1 in steps of 0.01.

SOLUTION:

#include #include #include void main() { float L,R,C,x,a,b,F; clrscr(); printf("Enter the value of L,R,C\n"); scanf("%f %f %f",&L,&R,&C); a={ (1/L*C) – (R*R/4*C*C) }; F=sqrt(a); Printf(“%f”,F); getch(); }

EXERCISE NO.3.11: Write program to read a four digit integer and print the sum of its digit. Hints: Use / and % operators.

SOLUTION: #include #include void main() { int num,a,b,c,d,x,y,result; clrscr(); printf("Enter a number"); scanf("%d",&num); a=num%10; x=num/10;

b=x%10; y=x/10; c=y%10; d=y/10; result=a+b+c+d; printf("%d",result); getch(); }

EXERCISE NO. 3.12: Write a program to print the size of various data types in C.

SOLUTION: #include #include void main() { int m; clrscr(); m=sizeof(10); printf("Size=%d",m); getch(); }

EXERCISE NO.3.13: Given three values, write a program to read three values from keyboard and print out the largest of them without using if statement.

SOLUTION: #include #include void main() { int x,y,z,a,b; printf("Enter the value of x,y,z\n"); scanf("%d%d%d",&x,&y,&z); printf("largest\n"); a=(x>y)?x:y b=(a>z)?a:z printf("%d",b); } EXERCISE NO.3.14: Write a program to read two integer values m and n and to decide and print whether m is multiple of n.

SOLUTION: #include #include void main() { int m,n; printf("Enter m & n,m>=n:"); scanf("%d %d",&m,&n); if(m%n==0) printf("m is a multiple of n");

else printf("m is not a multiple of n"); getch(); }

EXERCISE N0.3.15: Write a program to read three values using scanf statement and print the following results: (a)Sum of the values (b) Average of the three values (c) Largest of the three (d) Smallest of the three.

SOLUTION: #include #include

void main()

{ int a,b,c,x,y; float sum, average; clrscr(); printf("Enter the value of a,b,c\n"); scanf("%d%d%d",&a,&b,&c); sum=(a+b+c); printf("sum=%f\n",sum); { average=sum/3; printf("average=%f\n",average);

} { printf("Largest\n"); x=(a>b)?a:b; y=(x>c)?x:c; printf("%d\n",y); } { printf("Smallest\n"); x=(a
}

EXERCISE NO.3.16: The cost of one type of mobile service is Rs.250 plus Rs.1.25 for each call made over and above 100 calls. Write a program to read customer codes and calls made and print the bill for each customer.

SOLUTION:

#include #include void main() { int code,call;

float bill; clrscr(); printf("Enter customer code and number of calls made:"); scanf("%d %d",&code,&call); bill=250+(call*1.25); printf("Bill=%f",bill); getch(); }

EXERCISE NO.3.17: Write a program to print a table of sin and cos functions for the interval 0 180 degrees in increments of 15 as shown below. -----------------------------------------------------------------------------------------------x(degees) sin(x) cos(x) O

…….

…….

15

.……

…….

…..

…….

SOLUTION: #include #include #include #define p1 3.1416 #define MAX 180

void main() {

int i;

…….

float x,y,z; clrscr(); i=0; printf("x(degree) sin(x) cos(x)\n"); while(i<=MAX) { x=(p1/MAX)*i; y=sin(x); z=cos(x); printf("%d\n %f\n %f\n",i,y,z); i=i+15; } getch(); }

EXERCISE NO.3.18: Write a program to compute the values of square-roots and squares of the number 0 to 100 in steps 10 print the output in a tabular form as shown below. -----------------------------------------------------------------------------------------------number Square-root square 0

0

0

100

10

10000

SOLUTION:

#include #include #include void main()

{ /*......square root and square of numbers 0 to 100.....*/ int i,y; float x; clrscr(); printf("Number\tSquare root\tSquare\n\n"); for(i=0;i<=100;i++) { x=sqrt(i); y=i*i; printf("%d\t%f\t%d\n",i,x,y); } getch(); }

EXERCISE NO.3.19: Write a program that determines whether a given integer is odd or even and displays the number and description on the same line.

SOLUTION: #include #include void main() { int x; clrscr(); printf("Enter the integer number:"); scanf("%d",&x); if(x%2==0) printf("THe number %d is even",x);

else printf("The number %d is odd",x); getch(); } EXERCISE NO.3.20: Write a program to illustrate the use of cast operator in a real life situation.

SOLUTION: include #include void main() { float sum; int n; clrscr(); sum=0; for(n=1;n<=10;++n) { sum=sum+1/(float)n; printf("%2d %6.4f\n",n,sum); } getch(); }

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4 comments: 1. Niteesh BihadeJuly 30, 2012 at 2:30 AM

Thank you for your tutorial and lectures. I am just posting a more simple code to your question 3.2 EXERCISE NO.3.2: Write a program that reads a floating-point number and then displays right-most digit of the integral part of the number.

#include main() { float int

a; num;

printf("Enter scanf("%f",

a

num printf("Rightmost }

real

= integer\t

number:\t"); &a); (int)a%10; num);

%d",

Reply 2. NiteeshAugust 1, 2012 at 2:31 AM Code edit for solution 3.10. Please edit the given values appropriately to suit your solution needs. The code written below is edited and is more in accordance to the question asked.

#include #include main() { float float float

l step

while(c<=limit) {

= =

0.01, frequency

1000.0, limit

=

r 0.1, =

= c

=

500.0; 0.01; 0;

frequency printf("Step c } }

= -

sqrt( (1/l*c) %f\tFrequency =

%f\n",

((r*r)/(4*c*c)) ); step, frequency); c+step;

Reply 3. NiteeshAugust 1, 2012 at 2:50 AM 3.11

A

more

elegant

and

easy

to

understand

code

for

beginners...

#include main() { int printf("Enter scanf("%d",

a; four

digit

integer:

\t"); &a);

//Remember always division operator gives quotient wheras the modulo operator gives remainder int a1 = a/1000; // a = 2356, a1 = 2 int a2 = a%1000; // a2 = 356 int a3 = a2/100; // a3 = 3 int a4 = a2%100; //a4 = 56 int a5 = a4/10; //a5 = 5; int a6 = a4%10; //a6 = 6; printf("\n\n%d", a1); printf("\n%d", a3); printf("\n%d", a5); printf("\n%d", a6); printf("\n-----------------------------------------------------------------------------------\ n\n"); int printf("Sum }

sum of

= Digits

-

a1+a3+a5+a6; %d", sum);

3.12 - Write a program to print the size of various data types in C. Commentor's note - The code published above by the blogger is flawed. Below I present the correct solution. #include main() { int int int int printf("Size printf("\nSize printf("\nSize printf("\nSize

i f d c of of of of

= = = = data data data data

type integer type float type double type char -

sizeof(int); sizeof(float); sizeof(double); sizeof(char); %d", %d", %d", %d\n\n\n",

}

E.Balagurusamy C PROGRAMMING :CHAPTER-4 4.6 STATES ERRORS,IF ANY,IN THE FOLLOWING STATEMENTS. [A] :scanf(“%c %f %d”,city,&price,&year); =NO ERROR. [B] :scanf(“%s %d”,city,amount);

i); f); d); c);

= THERE WILL BE A & BEFORE AMOUNT. [C] :scanf(“%f %d”,&amount,&year); =NO ERROR. [D] :scanf(\n”%f”,root); =\n will remain into double quote. [E] :scanf(“%c %d %ld”,*code,&count,root); =* IS NOT ALLOWED BEFORE CODE AND &WILL STAY BEFORE ROOT.

4.7 WHAT WILL BE THE VALUES STORED OF THE VARIABLES YEAR AND CODE WHEN THE DATA 1988,X ? [A] :scanf(“%d %c”,&year,&code); =YEAR STORS 1988 AND CODE STORS X. [B] :scanf(“%c %d”,&year,&code); = YEAR STORS X AND CODE STORS 1988. [C] :scnaf(“%d %c”,&code,&year); =CODE STORS 1988 AND YEAR STORS X.

4.8 COUNT,PRICE,CITY HAVE VALUES: COUNT=1275, PRICE=235.74, CITY=CAMBRIDGE.

WHAT WILL BE THE OUTPUT THE STATEMENT ? [A] :printf(“%d %f”,count,price); OUTPUT=1275 235.75. [B] :printf(“%d %f”,price,count); OUTPUT=36576 790980 [C] :printf(“%c”,city); OUTPUT=CAMBRIDGE

4.9 SHOW THE WRONG OF THE OUTPUT STATEMENTS. [A] :printf(“%d.7.2%f”,year,amount); WRONG=7.2 SHOULD REMAIN AFTER THE % [B] :printf(“%-s,%c”\n,city,code); WRONG=COMMA IS NOT ALLOWED AND \n SHOULD STAY INTO QUOTATION. [C] :printf(“%f %d %s”,price,count,city); =NO WRONG.

4.10 WHAT VALUES DOSE THE COMPUTER ASSIGN OF THIS INPUT STATEMENTS? Scanf(“%4d %*d”,&year,&code,&count); IF DATA KYED IN 19883745 0UTPUT=1988.

4.11 HOW CAN WE USE getcher() FUNCTION TO MULTICHARACTER STRINGS? =

BY INCLUDING SINGLE QUOTATION OVER MULTICHARACTER WE CAN USE getchar() FUNCTION.

4.12 HOW CAN WE USE putchar() FUNCTION TO MULTICHARACTER STRINGS? =

BY INCLUDING SINGLE QUOTATION OVER MULTICHARACTER WE CAN USE putchar() FUNCTION.

4.13 WHAT IS THE PURPOSE OF scanf() FUNCTION? =IF WE WANT TO TAKE DATA AFTAR RUNNING THE PROGRAMM THEN WE USE scanf FUNCTION.

4.14 DESCRIBE THE PURPOSE OF COMMONLY USED CONVERSION CHARACTERS IN A scanf() FUNCTION ? =IT INDICATES WHAT TYPES OF DATA WE TAKE AS INPUT.

4.15 WHAT HAPPENS WHEN AN INPUT DATA ITEM CONTAIN ?

[A] MORE CHARACTERS THAN SPECIFIED FIELD WIDTH. =VALUE WILL BE RIGHT-JUSTIFIED. [B] FEWER CHARACTER THAN SPECIFIED FIELD WIDTH. =VALUE WILL BE LEFT-JUSTEFIED. 4.16 WHAT IS THE PURPOSE OF printf() FUNCTION ? =IT IS USED TO SHOW ANYTHIG ON OUTPUT. 4.17 DESCRIBE THE PURPOSE OF COMMONLY USED CONVERSION CHARACTERS IN A printf() FUNCTION ? = IT INDICATES WHAT TYPES OF DATA WE WANT TO SHOW ON OUTPUT.

4.18 WHAT HAPPENS WHEN AN 0UTPUT DATA ITEM CONTAIN ? [A] MORE CHARACTERS THAN SPECIFIED FIELD WIDTH. =VALUE WILL BE RIGHT-JUSTIFIED. [B] FEWER CHARACTER THAN SPECIFIED FIELD WIDTH.

=VALUE WILL BE LEFT-JUSTEFIED. Problem no. 4.1:Given the string“WORDPROCESSING”, Write a program to read the string from the terminal and Display the same in the following format: (a)WORD PROCESSING (b)WORD PROCESSING (c) W.P.

Solution: #include #include void main() { char s[10],d[11]; clrscr(); printf("Enter the string: "); scanf("%4s%10s",s,d); printf("(a)%s %s\n",s,d); printf("(b)%s\n%s\n",s,d); printf("(c)%.1s.%.1s",s,d); getch(); }

Output:

Enter the string: WORDPROCESSING (a) WORDPROCESSING (b) WORD PROCESSING (c) W.P. Problem no. 4.2: Write a program to read the values of x and y and print the results of the following expression in one line: (a)(x+y)/(x-y)

(b)(x+y)/2

Solution: #include #include void main() { float x,y,a,b,c; clrscr(); printf("Enter the value of x & y: "); scanf("%f%f",&x,&y); if(x-y==0)

printf("(a)=imagine"); else

(c)(x+y)*(x-y)

{ a=(x+y)/(x-y); printf("(a)=%.2f",a); } b=(x+y)/2; c=(x+y)*(x-y); printf(" (b)=%.2f (c)=%.2f",b,c); getch(); }

Output: Enter the value of x & y: 4 3 (a)=7.00 (b)=3.50 (c)=12.00 Enter the value of x & y: 7 7 (a)= imagine (b)=7.00 (c)=0.00

Problem no. 4.3: Write a program to read the following numbers, round them off to the nearest integers and print out the results in integer form: 35.7

50.21

-23.73

-46.45

Solution: #include #include void main() { int p,i; float a; clrscr(); printf("ENTER REAL NUMBER FOR GET NEAREST INTEGER NUMBER\n"); for(i=1;i<=4;i++) { scanf("%f",&a); if(a>=0) p=a+0.5; else p=a-0.5; printf("\nNEAREST INTEGER NUMBER OF %f IS= %d\n",a,(int)p); } getch(); }

Output: ENTER REAL NUMBER FOR GET NEAREST INTEGER NUMBER 35.7 NEAREST INTEGER NUMBER OF 35.7 IS= 36 ENTER REAL NUMBER FOR GET NEAREST INTEGER NUMBER 50.21 NEAREST INTEGER NUMBER OF 50.21 IS=50

ENTER REAL NUMBER FOR GET NEAREST INTEGER NUMBER -23.73 NEAREST INTEGER NUMBER OF -23.73 IS= -24 ENTER REAL NUMBER FOR GET NEAREST INTEGER NUMBER -46.45 NEAREST INTEGER NUMBER OF -46.45 IS= -46

Problem no. 4.4:write a program that read 4 floating values in the range, 0.0 to20.0, and prints a horizontal bar chart to represent these values using the character * as the fill character. For the purpose of the chart, the values may be rounded off to the nearest integer . For the example , the value 4.36 should be represented as follos, * * * * * * * * * * * * Solution: #include #include

void main() { float a1,a2,a3,a4; int x,y,z,t,i; clrscr();

4.36

printf("Enter four float number:"); scanf("%f%f%f%f",&a1,&a2,&a3,&a4); x=a1+0.5;y=a2+0.5;z=a3+0.5;t=a4+0.5; printf("The horizontal bar chard is:\n"); for(i=0;i
Output: Enter four float number: 4.85 4.36 3.12 5.47 The horizontal bar chard is: * * *

* * 4.85

* * *

*

* * * * * *

4.36

3.12 *

*

5.47

Problem no.4.5: Write a program to demonstrate the process of multiplication. The program should ask the

user to enter two two digit integer and print the product of integers as shown bellow. 45 X

37

7x45 is 3x45is Add them

315 135 1665

Solution: #include #include void main() { int a,b,c,p; clrscr(); printf("Enter 2 two digits number:"); scanf("%d%d",&a,&b); printf(" \t%4d\n\tx%3d\n",a,b); printf("\t------\n"); p=b/10; c=b%10; printf("%dx%dis%6d\n",c,a,c*a); printf("%dx%dis%5d\n",p,a,p*a); printf("\t-------\n"); printf("Add them %d\n",a*b);

printf("\t-------"); getch(); }

Output: 45 X 7x45 is 3x45is Add them

37 315 135 1665

Problem no.4.6: Write a program to read three integers from the keyboard using one scanf statement and output them on one line using: (a)three printf statements, (b)only one printf with conversion specifiers and (c) only one printf without conversion specifiers. Solution: #include #include void main() { int x,y,z; clrscr();

printf("Enter three integer value of x,y,&z:"); scanf("%d%d%d",&x,&y,&z); printf("(a) X=%d,",x); printf("Y=%d,",y); printf("Z=%d\n",z); printf("(b) X=%3d, Y=%2d, Z=%2d\n",x,y,z); printf("(c) X= %d, Y=%d, Z= %d",x,y,z); getch(); }

Output: Enter three integer value of x,y,&z: 45 27 89 (a) X=45, Y=27, Z=89 (b) X=45, Y=27, Z=89 (c) X=45, Y=27, Z=89

Problem no.4.7: Write a program that prints the value 10.45678 in exponential format with the following specifications: (a)correct to two decimal place, (b)correct to four decimal place and (c)correct to eight decimal place. Solution: #include #include int main(void) { float a=10.45678,x,y,z; clrscr(); printf("%8.2e\n%10.4e\n%10.8e",a,a,a); getch(); return 0; }

Output: 1.04e+01 1.0456e+01 1.04567804e+01

Problem no.4.98 Write a program to print the value 345.6789 in fixed-point format with the following specifications: (a)correct to two decimal place, (b)correct to four decimal place and (c)correct to zero decimal place. Solution: #include #include void main() { float a=345.6789; clrscr(); printf("The two decimal place is: %.2f\n",a); printf("The five decimal place is: %.5f\n",a);

printf("The zero decimal place is: %.0f",a); getch(); }

Output: The two decimal place is: 345.67 The five decimal place is: 345.67889 The two decimal place is: 345

Problem no.4.9: Write a program to read the name ANIL KUMAR GUPTA in three parts using the scanf statement and to display the same in the following format using the printf statement.

(a) ANIL K. GUPTA (b) A. K. GUPTA (c)

GUPTA A. K. Solution:

#include #include void main() { char s[6],d[6],c[6]; clrscr(); printf("Enter the string:"); scanf("%5s%5s%5s",s,d,c); printf("(a) %s %.1s. %s\n",s,d,c); printf("(b) %.1s.%.1s.%s\n",s,d,c); printf("(c) %.1s.%.1s.\n",c,s,d);

getch();

}

Output: Enter the string: ANIL KUMAR GUPTA (a)

ANIL K. GUPTA

( b) A. K. GUPTA (d) GUPTA A. K.

Problem no.4.10: Write a program to read and disply the following table of data Name

Code

Price

Fan

67831

1234.50

Motor

450

5786.70

The name and code must be left-justified and price must be right-justified . Solution: #include #include void main() { int code1,code2; float price1,price2; char name1[10],name2[10]; clrscr();

printf("Enter first name ,code and price :"); scanf("%s%d%f",name1,&code1,&price1); printf("Enter second name ,code and price :"); scanf("%s%d%f",name2,&code2,&price2); printf("Name\tCode\tPrice\n"); printf("%-s\t%-d\t%.2f\n",name1,code1,price1); printf("%-s\t%-d\t%.2f\n",name2,code2,price2);

getch(); }

Output: Enter first name ,code and price :

Fan

67831

1234.50

Enter second name ,code and price :

Motor

450

Name

5786.70

Code

Price

Fan

67831

1234.50

Motor

450

5786.70

Chapter 5 DECISION MAKING AND BRANCHING REVIEW QUESTION: RQ-5.1:State whether the following are true or false : (a)When if statements are nested , the last else gets associated with the nearest if without an else. Ans: False. (b)One if can have more than one else clause. Ans: False.

(c)A switch statement can always be replaced by a series of if..else statements. Ans: False. (d)A switch expression can be of any type. Ans: False. (e)A program stops its execution when a break statement is encountered. Ans: False. (f)Each expression in the else if must test the same variable. Ans: True. (g)Any expression can be used for the if expression. Ans: True. (h)Each case label can have only one statement. Ans: True. (i)The default case is required in the switch statement. Ans: True. (j)The predicate !( (x>=10) (y==5) ) is equivalent to (x<10) && (y!=5 ). Ans: True.

RQ-5.2:Fill in the blanks in the following statements: (a)The ……….operator is true only when both the operands are true. Ans: logical AND (&&). (b)Multiway section can be accomplished using an else if statement or the . ……………statement. Ans: switch. (c)The……….. statement when executed in a switch statement causes. immediate exit from the structure Ans: break. (d)The ternary conditional expression using the operator ?: code be easily coded using ………..statement. Ans: if…else. (e)The expression !(x!=y)can be replaced by the expression………… Ans: x==y.

RQ-5.3:Find errors, if any, in each of the following segments: Solution: (a)if((x+y=z) && (y>0) ) printf(" "); Ans: Error. Correct ans: if((x+y==z) && (y>0) )

printf(" "); (b) if (code >1) a= b+c else a=0 Ans: Error. Correct ans: if (code >1) a= b+c; else a=0; (c) if(p>0) || (q <0) printf("Sign is negative”); Ans: Error. Correct ans:if((p>0) || (q <0)) printf("Sign is negative”);

RQ-5.4:The following is a segment of a program: x=1; y=1; if(n>0) x=x+1; y=y-1; printf("%d %d", x,y); what will be the values of x and y if n assumes a value of (a) 1and (b) 0.

Solution: (a)The value of x is 2 & y is 0. (b)The value of x & y is imaginary.

RQ-5.5:Rewrite each of the following without using compound relations: (a) if(grade<=59&&grade>=50) second=second+1; Solution: if(grade<=59) second=second+1; if(grade>=50) second=second+1;

(b) if ( number>100||number<0) printf(“Out of range”);

else sum=sum+number; Solution: if ( number>100) printf(“Out of range”); else if(number<0) printf(“Out of range”); else sum=sum+number; (c) if (M1>60&&M2>60||T>200) printf(“Admitted\n”); else printf (“Not admitted”); Solution: if (M1>60) printf (“Admitted\n”); if (M2>60) printf (“Admitted\n”); else if(T>200) printf (“Admitted\n”); else printf (“Not admitted”);

RQ-5.6:Assuming x=10 ,state whether the following logical expressions are true or false: (a)x==10 && x>10 && !x Ans:False. (b)x==10 || x> 10 && !x Ans:True. (c)x==10 && x>10 ||!x Ans:False. (d)x==10 ||x>10 || !x Ans:True.

RQ-5.7:Find errors,if any, in the following switch related statements.Assume that the variables x and y are of int type and x=1 and y=2. Solution: (a)switch(y); Ans: Error. Correct ans: switch(y) (b)case 10;

Ans: Error. Correct ans: case 10: (c)switch(x+y) Ans:No error. (d)switch(x) {Case 2: y= x+y; break}; Ans: Error. Correct ans: switch(x) {Case 2: y= x+y; break;}

RQ-5.8:Simplify the following compound logical expressions: (a) !(x<=10) Ans:(x>10) (c)!((x+y==z)&&!(z>5)) Ans: (x
(b)!(x==10)||!((y==5)||(z<0)) Ans: (x>0) (d)!((x<=5)&&(y==10)&&(z<5)) Ans: (x>5)

RQ-5.9:Assuming that x=5, y=0,and z=1 initially ,what will be their values after executing the following code segments? (a)if(x && y) x=10; else y=10; Output: 10 10 (b)if(x|| y ||z) y=10; else z=0; Output: 1 0 (c)if(x) if(y) z=10; else z=0; Output: 10 0 (d)if(x ==0 || x && y) if(!y)

z=0; else y=1; Output: 0 1

RQ-5.10:Assuming that x=2,y=1 and z=0 initially ,what will be their values after executing the following code segments? (a) switch(x) { case 2: x=1; y=x+1; case 1: x=0; break; default: x=1; y=0; } Output: 1 0 (b) switch(y) { case 0: x=0; y=0; case 2: x=2; z=2; default: x=1; y=2; } Output: 0 0 0

RQ-5.11:Find the error ,if any,in the following statements: Solution: (a)if(x>=10) printf("\n"); Ans: No error. (b)if(x>=10) printf("OK"); Ans: No error. (c)if(x==10) printf ("Good"); Ans : No error. (d)if(x=<10) printf("Welcome"); Ans : Error. Correct ans: if(x<=10) Printf(“Welcome”);

RQ-5.12:What is the output of the following program? Program: main() { int m=5; if(m<3) printf("%d", m+1); else if (m<5) printf("%d", m+2); else if (m<7) printf("%d", m+3); else printf("%d", m+4); getch(); }

Output: 8

RQ-5.13:What is the output of the following program? Program: main () { int m=1; if( m==1) { printf ("Delhi");

if(m==2) printf("Chennai"); else printf("Banglore"); } else Printf("END"); getch(); }

Output: 1 Delhi 2 Chennai 3 Banglore

RQ-5.14:What is the output of the following program? Program: main() { int m; for(m=1; m<5; m++) printf("%d\n",(m%2) ? m : m*2); getch(); }

Output: 1 4 3 8

RQ-5.15:What is the output of following program? Program: main() { int m,n,p; for(m=0; m<3;m++) for(n=0;n<3;n++) for(p=0;p<3;p++) if(m+n+p==2) goto print;

print: printf("%d %d %d",m,n,p); getch(); }

Output: 0 0 2

RQ-5.16:What will be the value of x when the following segment is executed? int x=10,y=15; x= (x
Solution: The value of x after execution is :-25.

RQ-5.17:What will be the output when the following segment is executed? int x=0; if(x>=0) if(x>0) printf("Number is positive"); else printf("Number is negative");

Output: 0 Number is positive 1 Number is negative

RQ-5.18: What will be the output when the following segment is executed? Program: char ch = ‘a’ switch(ch) { case ‘a’: printf(“A”); case ‘b’: printf(“B”); case ‘c’: printf(“C”); }

Output: a A b B c C

RQ-5.19:What will be the output of the following segment when executed? Program: main() { int x=10,y=20; if(( x10) printf("%d",x); else printf("%d",y); getch(); }

Output: 10

RQ-5.20:What will be the output of the following segment when executed? Program: main() { int a=10, b=5; if(a>b) { if(b>5) printf("%d",b); } else printf("%d",a); getch(); }

Output: 10

CHAPTER 5

Decision Making and Branching EXERCISE-5.1 Write a program to determine whether a given number is odd or even and print the message: NUMBER IS EVEN or NUMBER IS ODD (a) without using else option, and (b) with using else option. Solution: (a) without using else option: /*………………even or odd……………*/ #include #include void main() { int n; clrscr(); printf(“Enter a number\n”) scanf("%d",&n); if(n%2==0) printf("NUMBER IS EVEN "); if(n%2==1) printf("NUMBER IS ODD "); getch(); }

(b) with else option: /*………………even or odd……………*/ #include #include void main() { int n; clrscr(); printf(“Enter a number\n”) scanf("%d",&n); if(n%2==0) printf("Even"); else printf("Odd"); getch(); }

EXERCISE-5.2 Write a program to find the number of and sum of all integers greater than 100 and less than 200 that are divisible by 7. Solution: /*…..number between 100-200 divisible by 7……*/ #include #include void main() { int i,n,r,sum; sum=0; clrscr(); for(i=100;i<=200;i++) { r=i%7; if(r==0) { printf(" %d",i); sum=sum+i; } printf(“Sum=%d”,sum); } getch(); }

EXERCISE-5.3 A set of two linear equations with two unknowns x1 and x2 is given below: ax1 +bx2=m and cx1+dx2=n The set has unique solution x1= and x2= provided the determinate ad-cb is not equal to zero. Write a program that will read the values of constants a,b,c,d,m and n and compute the values of x1 and x2 .An appropriate message should be printed if ad-cb=0. Solution: /*…….two linear equation………*/ #include #include void main() { float a,b,c,d,m,n,x1,x2; clrscr(); printf("Input a,b,c,d,m,n:\n"); scanf("a=%f b=%f c=%f d=%f m=%f n=%f",&a,&b,&c,&d,&m,&n); x1=(m*d-b*n)/(a*d-c*b); x2=(n*a-m*c)/(a*d-c*b); if((a*d-c*b)!=0) printf("x1=%f x2= %f",x1,x2); else printf("The value is infinity.\n"); getch(); }

EXERCISE-5.4 Given a list of marks ranging from 0 to 100, write a program to print number of students: (a)Who have obtained more than 80 marks, (b) who have obtained more than 60 marks, (c)Who have obtained more than 40 marks, (d) who have obtained 40 or less marks, (e)In the range 81 to 100, (f) in the range 61 to 80, (g)in the range 41 to 60, and (h) in the range 0 to 40. The program should use a minimum numbers of if statements. Solution: /*….marks obtain……*/ #include #include void main() { int marks,count,a,b,c,d,i; a=0; b=0; c=0;d=0; clrscr(); printf("Input 20 boy's marks\n"); for(i=1;i<=20;i++) { scanf("%d",&marks); if(marks>80) a++; else if(marks>60) b++; else if(marks>40) c++; else if(marks<=40) d++; } printf("Number of students who have obtained more than 80 marks=%d\nNumber of students who have obtained more than 60 marks=%d\n Number of students who have obtained more than 40 marks=%d\n Number of students who have obtained 40 or less marks=%d",a,b,c,d);

getch(); }

EXERCISE-5.5 Admission to a professional course is subjects to the following conditions: (a) Marks in Mathematics>=60 (b) Marks in Physics>=50 (c) Marks in Chemistry>=40 (d) Total in all three subjects>=200 or Total in Mathematics and Physics>=150 Given the marks in the three subjects, write a program to process the applications to list the eligible candidates. Solution: /*……..admission for a professional course……*/ #include #include void main() { int r,m,c,p,b; clrscr(); printf("Input Mathmatics,Physics and Chemistry"); scanf("%d%d%d",&m,&p,&c); r=m+p+c; b=m+p; if(m>=60&&p>=50&&c>=40&&r>=200&&b>=150) printf("The candidate is eligible"); else printf("The candidate is not eligible"); getch(); }

EXERCISE-5.7: Shown below is a Floyd’s triangle . 1 23 456 7 8 9 10 11………..15 79........ .. .. .. .. ..91 (a) Write a program to print this triangle. Solution: /*……….Floyd’s triangle………..*/ #include #include void main() { int i,j,count,n; clrscr(); count=0; printf("\n\nHow many rows of Floyd triangle: "); scanf("%d",&n); for(i=1;i<=n;i++) { for(j=1;j<=i;j++) { count++; printf("%d",count); printf(" "); } printf("\n"); }

getch(); }

(b) Modify the program the following from of Floyd’s triangle. 1 01 101 0101 10101 Solution: /*……….Floyd’s triangle………..*/ #include #include void main() { int i,j,count,n; clrscr(); count=0; printf("\n\nHow many rows of Floyd triangle: "); scanf("%d",&n); for(i=1;i<=n;i++) { for(j=2;j<=i+1;j++) { printf("%d",(i+j)%2); printf(" "); } printf("\n"); } getch(); }

EXERCISE-5.8 A cloth showroom has announced the following seasonal discounts on purchase of items: Purchase amount

Discount Mill cloth Handloom items 0-100 5% 101-200 5% 7.5% 201-300 7.5% 10.0% Above300 10.0% 15.0% Write a program using switch and if statements to compute the net amount to be paid by a coustomer. Solution: /*………….marketing of a showroom………………*/ #define MC1 0 #define MC2 0.05 #define MC3 0.075 #define MC4 0.10 #define HI1 0.05 #define HI2 0.075 #define HI3 0.10 #define HI4 0.15 #include #include void main() { float price,net,discount; int level,jobnumber;

clrscr(); input: printf("Enter level jobnumber and purchase amount\n"); printf("Enter zero for level to End\n"); scanf("%d%d%f",&level,&jobnumber,&price); if(level==0) goto stop; if(0<=price<=100) level=1; else if(101<=price<=200) level=2; else if(201<=price<=300) level=3; else level=4; switch(level) { case 1: discount=MC1+HI1; break; case 2: discount=MC2+HI2; break; case 3: discount=MC3+HI3; break; case 4: discount=MC4+HI4; break; default: printf("Error in level code\n"); goto stop; } net=price-(price*discount); printf("Net amount=%f\n",net); goto input; stop:printf("\n\nEND OF THE PROGRAM"); getch(); }

EXERCISE-5.9 Write a program that will read the value of x and evaluate the following function y= using (a) nested if statements. (b) else if statements and (c) conditional operator ? Solution: /*…………evaluate the equation………..*/ (a)nested if statements: #include #include void main() { float x,y; clrscr(); printf("Input x\n"); scanf("%f",&x); if(x!=0) { if(x>0) printf("y=1"); if(x<0) printf("y=-1"); } if(x==0) printf("y=0"); getch(); }

(b)else if statements: #include #include void main() { float x,y; clrscr(); printf("Input x\n"); scanf("%f",x); if(x!=0) { if(x>0) { printf("1"); } else printf("-1"); } else printf("0"); getch(); } (c)conditional operator: #include #include void main() { clrscr(); float y,x; printf("Input x\n"); scanf("%f",&x); y=(x!=0)?((x>0)?1:-1):0; printf("%d",y); getch(); }

EXERCISE-5.10 Write a program to compute the real roots of a quadratic equation ax2+bx2+c=0 The roots are given by the equtions: x1 and x2 The program should request for the values of the constants a,b and c print the values of x1 and x2.Use the following: (a) No solution, if both a and b are zero (b) There is only one root if a=0(x=-c/b) (c) There are no real roots, if b2-4ac is negative (d) Otherwise, there no real roots Test your program with appropriate data so that all logical paths are working as per your design. Incorporate appropriate output messages. Solution: /*…….roots of quadratic equation ….*/ #include #include #include void main() { float a,b,c,x,discriminant,root1,root2; clrscr(); printf("Input values of a, b and c\n"); scanf("%f %f %f",&a,&b,&c); discriminant=b*b-4*a*c; if(a==0&&b==0) printf("No solution\n"); else if(a==0) { x=-(c/b); printf("x=%f",x);

} else if(discriminant<0) printf("Roots are imaginary\n"); else { root1=-b+sqrt(discriminant)/2*a; root2=-b-sqrt(discriminant)/2*a; printf("Root1=%f Root2=%f",root1,root2); } getch(); } EXERCISE-5.11: Write a program to read three integer values from the keyboard and displays the output stating that they are the sides of right-angled triangle. Solution: /*………………right-angled triangle……..*/ #include #include void main() { int a,b,c,x,y,z; clrscr(); printf("Input three integer values a b and c\n"); scanf("%d%d%d",&a,&b,&c); x=a*a; y=b*b; z=c*c; if(a>b&&a>c&&(x==y+z)) printf("The values are sides of right-angled triangle"); else if(b>a&&b>c&&(y==x+z)) printf("The values are sides of right-angled triangle"); else if(c>a&&c>b&&z==x+y) printf("The values are sides of right-angled triangle"); else printf("The values are not sides of right-angled triangle"); getch(); }

EXERCISE-5.12: An electricity board charges the following rates for the use of electricity: For the first 200 units: 80 per unit For the next 100 units: 90per unit Beyond 300 units: Rs.1.00 per unit All users are charged a minimum of Rs. 100 as meter charge. If the total amount is more than Rs.400, then an additional surcharge of 15% of total amount is charged. Write a program to read the names of users and number of units consumed and print out the charges with names. Solution: /*………….pay bill…………..*/ #include #include void main() { float units,total,net; char name; clrscr(); printf("Input users name and units\n"); scanf("%s %f",&name,&units); { if(units<=200) total=100+0.80*units; else if(units<=300) total=100+0.90*units; else if(units>300) total=100+1.00*units; } if(total>400) { net=total+total*0.15; printf("Total=%f",net); } else printf("Total=%f",total); getch(); }

EXERCISE-5.13: Write a program to compute and display the sum of all integers that are divisible by 6 but not divisible by 4 and lie between 0 to 100. The program should also count and display the number of such values. Solution: /*……numbers between 0-100 divisible by 6 but not divisible by 4….*/ #include #include void main() { int i,count; count=0; clrscr(); for(i=0;i<=100;i++) { if(i%6==0&&i%4!=0) { count=count+1; printf(" %d",i); } } printf(“\n”); printf("count=%d",count); getch(); }

EXERCISE-5.14 Write an interactive program that could read a positive integer number and decide whether the number is a prime number display the output accordingly. Modify the program to count all prime numbers that lie 100 to 200. [Note: A prime number is positive integer that is divisible only by 1 or by itself] Solution:

/*………….prime number …………*/ #include #include void main() { int i,j,count; count=0; clrscr(); printf("\n\nSeries of prime number from 100 to 200:\n"); for(i=100;i<=200;i++) { for(j=2;j<=i;j++) { if(i%j==0) break; } if(i==j) { printf("%4d\n",i); count+=1; } } printf("The countable number is: %d",count); getch(); }

EXERCISE-5.15: Write a program read a double-type value x that represents angle in radians and a character-type variable t that represents the type of trigonometric function and display the value of (a) sin(x), if s or S is a assigned to T, (b) cos(x), if c or C is assigned to T, and (c) tan(x), if t or T is assigned to T Using (i) if…else statement and (ii) switch statement. Solution-1: (i)if…else statement : /*……………trigonometric function……….*/ #include #include #include #include void main() { int x,c,s,d,t; clrscr(); float r,result;

s=1; c=2; t=3; printf(“Input the value of x and character value\n”); scanf("%d",&x); r=x*(180/3.1416); scanf("%d",&d); { if(d==1) result=sin(r); else if(d==2) result=cos(r); else if(d==3) result==tan(r);

else printf("no response."); } printf("\n%f",result); getch(); } Solution-2: (ii) switch statement:

/*………….trigonometric function…………..*/ #include #include #include void main() { int i,x; float v,r; char t; clrscr(); printf("Input the value of x\n"); scanf("%d",&x); r=x*(180/3.1416); printf("Input charecter"); scanf("%c",&t); switch(t) { case 's': case 'S': v=sin(r); case 'c': case 'C': v=cos(r); case 't': case 'T': v=tan(r); } printf("%f",v); getch(); }

Chapter-06

Decision making and looping REVIEW QUESTIONS 6.1 State whether the following statements are true or false: (a) The do… while statement first executes the loop body and then evaluate the loop control expression. Ans: True. (b) In a preset loop, if the body is executed n terms, the test expression is executed n+1 times. Ans: True. (c) The number of times a control variable is updated always equals the number of loop iterations. Ans: True. (d) Both the preset loops include initialization within the statement. Ans: True. (e) In a for loop expression, the starting value of the control variable must be less than its ending value. Ans: True. (f) The initialization, test condition and increment parts may be missing in a for statement. Ans: False. (g) While loops can be used to replace for loops without any change in the body of the loop. Ans: False. (h) An exit control loop is executed a minimum of a one line. Ans: False. (i) The use of continue statement considered as unstructured programming. Ans: True. (j) The three loop expressions used in a for loop header must be separated by commas. Ans: True. 6.2: Fill in the blanks in the following statements. (a) In an exit controlled loop, if body is executed n times, test condition is evaluated times.

Ans: (n-1) (b) The statements is use to skip a part of the statements in a loop. Ans: continue. (c) A for loop with the no test condition is known as loop. Ans: infinite (d) The sentinel controlled loop is also; known as loop. Ans: indefinite repetition. (e)In a counter controlled loop, variable known as is used to count the loop operation. Ans: definite repetition. 6.8 explain the operation of each of the following for loops. (a)for (n=1;n!=10;n+=2) sum=sum+n; Ans :The loop repeats 5 times. (b)for(n=5;n<=m;n-=1) sum+=n; Ans: The continue until n<=m where m initializes from 5 and decrements by 1. (c) for(n=1;n<=5) sum+=n; Ans: Since theren is no increment or decrement condition the loop repeats 5 times. (d) for(n=1; ;n+=1) sum+=n; Ans: The loop repeats infinity times. (e)for(n=1;n<5;n++) n=n-1; Ans: The loop repeats infinity times. 6.9: what would be the output of each of the following code segments? (a)count=5; while(count-- >0) printf(“count”); Output: 5 4 3 2 1 (b)count=5; while(-- count>0) Printf(“count”); Output: 4 3 2 1 (c) count=5; do printrf(“count”);

while(count>0) Output: 5 4 3 2 1 (d)for(m=10;m>7;m-=2) printf(“m”); output; 10 8 6.11:Analyse each of the program segment that follow the determine how many times the body of each loop will be executed. (a)x=5; y=50; while(x<=y) { x=y/x; ………………….. ………………….. } Ans: Infinity times (b) m=1; do { …………………… ………………………. m+=2; } while(m<10) Ans: 5 times. (c) int i; for(i=0;i<=5;i=i+2/3) { ………………….. ……………………. } Ans: Infinity times. (d) int m=10; Int n=7; while(m%n>=0) { ……………… m+=1;

n+=2; ……………. } Ans: 4 times. 6.12: Find errors, if any, in each of the following looping segments. Assume that all the variables have been declared and assigned values. (a)while(count!=10); { count=1; sum+=x; count+=1; } Error: while(count!=10); Correct Ans: while(count!=10) (b) name=0; do { name+=1; printf(“my name is Dinar\n”); while(name=1); Error: while (name=1); Correct Ans: while(name==1); (c) do; total+=value; scanf(“%f”,&value); while(value!=999); Error: do; Correct Ans: do (E) m=1; n=0; for(p=10;p>0;) p-=1; printf(“%f”,p); Error: for(p=10;p>0;) p-=1; printf(“%f”,p); Correct ans: for(p=10;p>0;) { p-=1;

printf(“%f”,p); } 6.13:Write a for statement to pront each of the following sequence of integers: (a) 1,2,4,8,16,32 Ans: for(i=1;i<=32;i=i*2) printf(“%d”,i); (b) 1,3,9,27,81,243 Ans: for(i=1;i<=243;i=i*i) printf(“%d”,i); (c) -4,-2,0,4 for(i=-4;i<=4;i=i+2) printf(“%d”,i); (d) -10,-12,-14,-18,-26,-42 for(i=-10;i<=-42;i=i-2) printf(“%d”,i); 6.14: Change the following for loops to while loops : (a)for(m=1;m<10;m=m+1) printf(“m”); Ans: m=1; while(m<10) { ……………. m++; } printf(“m”); (b)for(;scanf(“%d”,&m)!=-1;) printf(“m”); Ans: while(scanf(“%d”,&m)!=-1) printf(“m”); 6.16: What is the output of following code? Int m=100,n=0; while(n==0) { if(m<10) break; m=m-10; }

Output: No output 6.17: What is output of the following code? int m=0; do { if(m>10) continue; m=m+10; } while(m<50); printf(“%d”,m); Output: 50 6.18: What is the output of the following code? int n=0,m=1; do { printf(“m”); m++; } while(m<=n); Output: 1 6.19: What is the output of the following code? int n=0,m; for(m=1;m<=n+1;m++) printrf(“m”); Output: 1 6.20: When do we use the following statement? for(; ;) Ans : When we need an infinity loop the statement for(; ;) can be used.

CHAPTER-7

By Tanvir on January 15, 2013

4 Votes

7.1 Write a program for fitting a straight line through a set of points (xi, yi),i=1,2,3….n. The straight line equation is: Y =mx+c and the values of m and c are given by: m=((n ∑(xi,yi))- (∑xi)(∑yi) )/( n(∑xi2)-(∑xi)2) c=1/n(∑yi -m(∑xi)) All summations are from 1 to n. Answer: #include #include void main() { int i,n=10,v1,v2,x[10],y[10]; int total_x,total_y,total_xy,total_x2; float m,c,temp,temp1; clrscr(); printf(“Enter the values for x: “); for(i=0;i<10;i++) {

scanf(“%d”,&v1); x[i]=v1; } printf(“Enter the values for y: “); for(i=0;i<10;i++) { scanf(“%d”,&v2); y[i]=v2; } total_x=total_y=total_xy=total_x2=0; for(i=0;i<10;i++) { total_x=total_x+x[i]; total_y=total_y+y[i]; total_xy=total_xy+(x[i]*y[i]); total_x2=total_x2+(x[i]*x[i]); } temp= total_x*total_y; temp1=total_x*total_x; m=((n*total_xy)-(temp))/((n*total_x2)-temp1); c=((total_y)-(m*total_x))/n; printf(” \nThe equation of the straight line is: “);

printf(” Y=%fX+%f”,m,c); getch(); } Output Enter the values for x: 1 2 3 4 5 6 7 8 9 10 Enter the values for y: 1 2 3 4 5 6 7 8 9 10 The equation of the straight line is: Y=1.00000X+0.000000 7.2 The daily maximum temperature recorded in 10 cities during the month of January (for all 31 days) have been tabulated as follows: City 1 2 3 4 5 6 ……………………………10 Day 1 2 3 . . . .

31 7.2. Write a program to read the table elements into a two-dimensional array temperature, and to find the city and day corresponding to a) the highest temperature b) the lowest temperature Answer: //Write a program to read the table elements into a two-dimensional array temperature, and to find the city and day corresponding to //a) the highest temperature //b) the lowest temperature // Date : 16/03/2010 #include #include void main() { int Temp[2][2]; int i,j,City1,City2,MaxTemp,MinTemp; clrscr(); printf(“Enter temperature:–\n\n”); for(i=0;i<2;i++) { printf(“For City %d ->\n”,i); for(j=0;j<2;j++) { printf(“For Day %d ->”,j); scanf(“%d”,&Temp[i][j]); }

} clrscr(); printf(“Temperature Matix :— \n”); printf(” City \n “); for(i=0;i<2;i++) printf(“%d “,i+1); printf(“\n Day\n”); for(i=0;i<2;i++) { printf(” %d “,i+1); for(j=0;j<2;j++) { printf(” %d”,Temp[i][j]); } printf(“\n”); } MinTemp=MaxTemp=Temp[0][0]; City1=0; City2=0; for(i=0;i<2;i++) { for(j=0;j<2;j++)

{ if(MaxTempTemp[i][j]) { MinTemp=Temp[i][j]; City2=j+1; } } } printf(“\n\nHighest Temperature of City %d is %d\n”,City1,MaxTemp); printf(“Lowest Temperature of City %d is %d\n”,City2,MinTemp); getch(); }

7.3 An election is contested by 5 candidates. The candidate are numbered are 1 to 5 and the voting is done by marking the candidate number on the ballot paper. Write a program to read the ballots and count the votes cast for each candidate using an array variable count. In case, a number, read is outside the range 1 to 5,the ballot should be considered as a ‘spoilt ballot’ and the program should also count the

number of spoilt ballots.

Program:– /* An election is contested by 5 candidates. The candidate are numbered are 1 to 5 and the voting is done by marking the candidate number on the ballot paper. Write a program to read the ballots and count the votes cast for each candidate using an array variable count. In case, a number, read is outside the range 1 to 5,the ballot should be considered as a ‘spoilt ballot’ and the program should also count the number of spoilt ballots. */ // Date March 16,2010 #include #include void main() { int i,vote[5],c1=0,c2=0,c3=0,c4=0,c5=0,count=0,count_sp=0,v; clrscr(); printf(“Enter your votes for 5 candidates:”); for(i=1;i<=5;i++) { scanf(“%d”,&v); vote[i]=v; } for(i=1;i<=5;i++)

{ if(vote[i]==1) c1=c1+1; else { if(vote[i]==2) c2=c2+1; else { if(vote[i]==3) c3=c3+1; else { if(vote[i]==4) c4=c4+1; else if(vote[i]==5) c5=c5+1; } } } }

printf(” votes to candidate1=%d”,c1); printf(” \nvotes to candidate2=%d”,c2); printf(“\n votes to candidate3=%d”,c3); printf(” \nvotes to candidate4=%d”,c4); printf(” \nvotes to candidate5=%d”,c5); for(i=1;i<=5;i++) { if(vote[i]<=5) count=count+1; else count_sp=count_sp+1; } printf(” The number of valid votes is:%d”,count); printf(” \nThe number of spoilt votes is:%d”,count_sp); getch(); } Output Enter your votes for 5 candidates: 1 3 1 8

2 Votes to Candidate 1: 2 Votes to Candidate 2: 1 Votes to Candidate 3:1 Votes to Candidate 4:0 Votes to Candidate 5:0 The number of valid votes is: 4 The number of spoilt votes is: 1 7.51 The annual examination results of 10 students are tabulated as follows: Roll No. Subject1 Subject2 Subject3 . . . . __________________________________________________________________ __ Write a program to read the data and determine the following: (a) Total marks obtained by each student. (b) The highest marks in each subject and the Roll No. of the student who secured it. (c) The student who obtained the highest total marks.

Program:–

/* The annual examination results of 10 students are tabulated as follows: Roll No. Subject1 Subject2 Subject3 . . . . Write a program to read the data and determine the following: (a) Total marks obtained by each student. (b) The highest marks in each subject and the Roll No. of the student who secured it. (c) The student who obtained the highest total marks. */ // Date March 16,2010 #include #include #define MAX 10 void main() { int i,roll,m1,m2,m3,sub1[MAX],sub2[MAX],sub3[MAX]; int total_sub1,total_sub2,total_sub3,total[MAX]; int max,max1,max2,max3,roll1,roll2,roll3; clrscr();

printf(“Enter the marks for subject1 of all the students: “); for(i=0;i
max2=sub2[0]; max3=sub3[0]; max=total[0]; roll1=0; roll2=0; roll3=0; roll=0; for (i=0;i
roll3=i+1; } if(max
7.6 Given are one dimensional arrays A and B which are sorted in ascending order. Write a program to merge them into a single sorted array C that contains every item form array A and B, in ascending order.

Program:– // Given are one dimensional arrays A and B which are sorted in ascending // order. Write a program to merge them into a single sorted array C that contains // every item form array A and B, in ascending order. //Date: 16/03/2010 #include #include #define MAX 50 void main() { int a[MAX],b[MAX],c[MAX]; int ax,bx,cx,n,m,mn; clrscr(); ax=bx=cx=0; printf(“Enter no. of elements of array : “); scanf(“%d %d”,&n,&m); printf(“Enter elements of first array :\n”); for(i=0;i
for(i=0;i
bx++; cx++; } } else { while(ax
Program:– // Write a program that will read the values of elements of A and B and produce the // product matrix C. //Date: 16/03/2010 #include #include #define MAX 10 void main() { int a[MAX][MAX],b[MAX][MAX],c[MAX][MAX]; int i,j,k,row,col; clrscr(); printf(“Enter row of matrix”); scanf(“%d”,&row); printf(“Enter column of matrix”); scanf(“%d”,&col); printf(“Enter first matrix\n”); for(i=0;i
for(j=0;j
for(k=0;k
7.8 Write a program that fills a five-by-five as follows: • Upper left triangle with +1s • Lower right triangle with -1s • Right to left diagonal with zeros Display the contents of the matrix using not more than two printf statements.

Program:–

//Write a program that fills a five-by-five as follows: //• Upper left triangle with +1s //• Lower right triangle with -1s //• Right to left diagonal with zeros //Display the contents of the matrix using not more than two printf statements. // Date : 16/03/2010 #include #include void main() { int A[5][5]; int a,i,k,j; clrscr(); a=3; for(i=0;i<=3;i++) { for(j=0;j<=a;j++) { A[i][j]=+1; } a–; }

j=4; for(i=0;i<=4;i++) { A[i][j]=0; j–; } a=4; for(i=1;i<=4;i++) { for(j=4;j>=a;j–) { A[i][j]=-1; } a–; } printf(“Array is:–\n\n”); for(i=0;i<=4;i++) { for(j=0;j<=4;j++) printf(“%d “,A[i][j]); printf(“\n”); } getch(); } 7.9 Write a program to implement selection sort. Algorithm:– Step 1: Read Array A. Step 2: For k=0 to 9 repeat Step 3 to Step 8. Step 3: Compute Small=A[k] & Loc=k. Step 4: For i=0 to 9 repeat Step 5 to Step 7 otherwise go to Step 7. Step 5: Check Small>A[i] then go to Step 6 otherwise go to Step 4. Step 6: Compute Small=A[i] & Loc=i. Step 7: Compute A[Loc]=A[k], A[k]=Small.

Step 8: Display Sorted Array A. Flowchart:– Program:– //Write a program to implement selection sort. // Date : 16/03/2010 #include #include void main() { int A[10]; int i,k,Small,Loc; clrscr(); printf(“Enter Elements of Array:—\n”); for(i=0;i<=9;i++) scanf(“%d”,&A[i]); for(k=0;k<=9;k++) { Small=A[k]; Loc=k; for(i=k;i<=9;i++) if(Small>A[i]) { Small=A[i];

Loc=i; } A[Loc]=A[k]; A[k]=Small; } printf(“Sorted Array is:–\n\n”); for(i=0;i<=9;i++) printf(“%d “,A[i]); getch(); } 7.10 Write a program to implement Binary Search algorithm.

Program:– //Write a program to implement Binary Search algorithm. // Date : 16/03/2010 #include #include void main() { int Str[10];

int i,Beg,End,Mid,Item; clrscr(); Beg=0; End=9; Mid=(Beg+End)/2; printf(“Enetr Any Sorted Array:–\n”); for(i=0;i<10;i++) scanf(“%d”,&Str[i]); printf(“Enter Item Which U want to Search:–\n”); scanf(“%d”,&Item); while((Item!=Str[Mid])&&(Beg<=End)) { if(ItemEnd) printf(“Item Not Found\n”); else printf(“%d Found At Index %d\n”,Item,Mid); getch(); }

7.11 Write a program that will compute the length of a given character string.

Program:– //Write a program that will compute the length of a given character string. // Date : 16/03/2010 #include #include void main() { char Str[50]; int i,Len; clrscr(); Len=0; printf(“Enter a String:—\n”); scanf(“%[^\n]s”,&Str); for(i=0;Str[i]!=”;i++) Len=Len+1; printf(“Length of String is %d”,Len); getch(); } 7.12 Write a program that will count the number occurrences of a specified character in a given line of text.

Program:– //Write a program that will count the number occurrences of a specified character in a // given line of text. // Date : 16/03/2010 #include #include void main() { char Str[50],CheckChar; int i,Count,Len; clrscr(); Count=0; printf(“Enter a String:—\n”); scanf(“%[^\n]s”,&Str); Len=strlen(Str); fflush(stdin); printf(“Enter a charatcer:–\n”); scanf(“%c”,&CheckChar);

for(i=0;i<=Len;i++) if(CheckChar==Str[i]) Count=Count+1; printf(“Number of occurences of %c is %d”,CheckChar,Count); getch(); }

7.13 Write a program to read a matrix of size m*n and print its transpose.

Program:– //Write a program to read a matrix of size m*n and print its transpose. // Date : 16/03/2010 #include #include #define MAX 10 void main() { int A[MAX][MAX],C[MAX][MAX]; int Row,Col,i,j; clrscr();

printf(“Enter Number of Rows:–\n”); scanf(“%d”,&Row); printf(“Enter Number of Column:–\n”); scanf(“%d”,&Col); printf(“Enter Matrix:—\n”); for(i=0;i
printf(“%d “,C[i][j]); printf(“\n”); } getch(); } 7.3 An election is contested by 5 candidates. The candidate are numbered are 1 to 5 and the voting is done by marking the candidate number on the ballot paper. Write a program to read the ballots and count the votes cast for each candidate using an array variable count. In case, a number, read is outside the range 1 to 5,the ballot should be considered as a ‘spoilt ballot’ and the program should also count the number of spoilt ballots.

Algorithm:–

Step1. Initialize c1,c2, c3,c4,c5,count,count_sp with 0. Step2. For i=0 to i=5, repeat step3. Step3. Enter the value of v and store in vote[i] Step4. For i=0 to i=5, repeat from step5 till step14 and for i>5,go to step15. Step5. Check if vote[i]==1,if true, go to step6,if false go to step7. Step6.Calculate c1=c1+1 Step7. Check if vote[i]==2,if true, go to step8,if false go to step9. Step8.Calculate c2=c2+2 Step9.Check if vote[i]==3,if true, go to step10,if false go to step11. Step10. Calculate c3=c3+2 Step 11.Check if vote[i]==4,if true, go to step12,if false go to step13. Step12.Calculate c4=c4+2 Step13.Check if vote[i]==5,if true, go to step14,if false go to step15. Step14.Calculate c5=c5+2 Step15. Display c1,c2,c3,c4 and c5. Step16. For i=0 to i=5, repeat from step 17 to step, and i>5,go to step 20 Step17.Check if vote[i]<5,if true go to step18 and if false, go to step 19. Step18.count=count+1 and go to step 20. Step19.count_sp=count_sp+1 and go to step 20. Step20. Display count and count_sp Step21. Stop.

Flowchart:–

Program:–

/* An election is contested by 5 candidates. The candidate are numbered are 1 to 5 and the voting is done by marking the candidate number on the ballot paper. Write a program to read the ballots and count the votes cast for each candidate using an array variable count. In case, a number, read is outside the range 1 to 5,the ballot should be considered as a ‘spoilt ballot’ and the program should also count the number of spoilt ballots. */ // Date March 16,2010 #include #include void main() { int i,vote[5],c1=0,c2=0,c3=0,c4=0,c5=0,count=0,count_sp=0,v; clrscr(); printf(“Enter your votes for 5 candidates:”); for(i=1;i<=5;i++) { scanf(“%d”,&v); vote[i]=v; }

for(i=1;i<=5;i++) { if(vote[i]==1) c1=c1+1; else { if(vote[i]==2) c2=c2+1; else { if(vote[i]==3) c3=c3+1; else { if(vote[i]==4) c4=c4+1; else if(vote[i]==5) c5=c5+1; } } }

} printf(” votes to candidate1=%d”,c1); printf(” \nvotes to candidate2=%d”,c2); printf(“\n votes to candidate3=%d”,c3); printf(” \nvotes to candidate4=%d”,c4); printf(” \nvotes to candidate5=%d”,c5); for(i=1;i<=5;i++) { if(vote[i]<=5) count=count+1; else count_sp=count_sp+1; } printf(” The number of valid votes is:%d”,count); printf(” \nThe number of spoilt votes is:%d”,count_sp); getch(); } Output Enter your votes for 5 candidates: 1 3 1

8 2 Votes to Candidate 1: 2 Votes to Candidate 2: 1 Votes to Candidate 3:1 Votes to Candidate 4:0 Votes to Candidate 5:0 The number of valid votes is: 4 The number of spoilt votes is: 1

5.1 The annual examination results of 10 students are tabulated as follows:

Roll No.

Subject1

Subject2

Subject3

. . . . __________________________________________________________________ __

Write a program to read the data and determine the following: (a) Total marks obtained by each student.

(b) The highest marks in each subject and the Roll No. of the student who secured it. (c)

The student who obtained the highest total marks.

Algorithm:–

Step1. Declare Step2. For i=0 to i<10, Enter sub1[i] Step3. For i=0 to i<10, Enter sub2[i] Step4. For i=0 to i<10, Enter sub3[i]

Program:–

/* The annual examination results of 10 students are tabulated as follows: Roll No.

Subject1

Subject2

. . . . Write a program to read the data and determine the following: (a)

Total marks obtained by each student.

Subject3

(b) The highest marks in each subject and the Roll No. of the student who secured it. (c)

The student who obtained the highest total marks.

*/ // Date March 16,2010 #include #include #define MAX 10 void main() { int i,roll,m1,m2,m3,sub1[MAX],sub2[MAX],sub3[MAX]; int total_sub1,total_sub2,total_sub3,total[MAX]; int max,max1,max2,max3,roll1,roll2,roll3; clrscr(); printf(“Enter the marks for subject1 of all the students: “); for(i=0;i
scanf(“%d”,&sub3[i]); total_sub1=total_sub2=total_sub3=0; for(i=0;i
{ if(max1
printf(“\nThe highest marks in subject1 is %d and the roll number is %d”,max1,roll1); printf(“\nThe highest marks in subject2 is %d and the roll number is %d”,max2,roll2); printf(“\nThe highest marks in subject3 is %d and the roll number is %d”,max3,roll3); printf(“\n The highest total marks is %d and the roll number is %d “,max,roll); getch(); }

7.6 Given are one dimensional arrays A and B which are sorted in ascending order. Write a program to merge them into a single sorted array C that contains every item form array A and B, in ascending order.

Algorithm:–

Step 1: Read m, n, Array a & Array b. Step 2: Store 0 to ax, bx and cx.

Step 3: Compute mn=m+n Step 4: Repeat Step 5 to Step 8 while ax
Program:–

// Given are one dimensional arrays A and B which are sorted in ascending // order. Write a program to merge them into a single sorted array C that contains //

every item form array A and B, in ascending order.

//Date: 16/03/2010 #include #include #define MAX 50 void main() { int a[MAX],b[MAX],c[MAX]; int ax,bx,cx,n,m,mn; clrscr(); ax=bx=cx=0; printf(“Enter no. of elements of array : “); scanf(“%d %d”,&n,&m); printf(“Enter elements of first array :\n”); for(i=0;i
{ c[cx]=a[ax]; ax++; } else { c[cx]=b[bx]; bx++; } cx++; } if(ax==n) { while(bx
while(ax
Algorithm:–

Step 1: Read row, col, Array a and Array b.

Step 2: Display Array a and b. Step 3: For i=0 to row repeat Step 4 to Step 7 Step 4: For j=0 to col repeat Step 5 to Step 7 Step 5: Store 0 to c[i][j] Step 6: For k=0 to col repeat Step 7 Step 7: Compute c[i][j]=c[i][j]+(a[i][k]*b[k][j]) Step 8: Display c.

Flowchart:–

Program:–

// Write a program that will read the values of elements of A and B and produce the // product matrix C. //Date: 16/03/2010 #include #include #define MAX 10 void main() { int a[MAX][MAX],b[MAX][MAX],c[MAX][MAX]; int i,j,k,row,col; clrscr(); printf(“Enter row of matrix”); scanf(“%d”,&row); printf(“Enter column of matrix”);

scanf(“%d”,&col); printf(“Enter first matrix\n”); for(i=0;i
} for(i=0;i
7.8 Write a program that fills a five-by-five as follows:



Upper left triangle with +1s



Lower right triangle with -1s



Right to left diagonal with zeros Display the contents of the matrix using not more than two printf statements.

Algorithm:–

Step 1: Store Upper left triangle with +1s Step 2: Store Lower right triangle with -1s Step 3: Store Right to left diagonal with zeros Step 4: Display A

Flowchart:–

Program:–

//Write a program that fills a five-by-five as follows: //•

Upper left triangle with +1s

//•

Lower right triangle with -1s

//•

Right to left diagonal with zeros

//Display the contents of the matrix using not more than two printf statements. // Date : 16/03/2010 #include #include void main()

{ int A[5][5]; int a,i,k,j; clrscr(); a=3; for(i=0;i<=3;i++) { for(j=0;j<=a;j++) { A[i][j]=+1; } a–; } j=4; for(i=0;i<=4;i++) { A[i][j]=0; j–; } a=4; for(i=1;i<=4;i++) {

for(j=4;j>=a;j–) { A[i][j]=-1; } a–; } printf(“Array is:–\n\n”); for(i=0;i<=4;i++) { for(j=0;j<=4;j++) printf(“%d “,A[i][j]); printf(“\n”); } getch(); } 7.9 Write a program to implement selection sort.

Algorithm:–

Step 1: Read Array A.

Step 2: For k=0 to 9 repeat Step 3 to Step 8. Step 3: Compute Small=A[k] & Loc=k. Step 4: For i=0 to 9 repeat Step 5 to Step 7 otherwise go to Step 7. Step 5: Check Small>A[i] then go to Step 6 otherwise go to Step 4. Step 6: Compute Small=A[i] & Loc=i. Step 7: Compute A[Loc]=A[k], A[k]=Small. Step 8: Display Sorted Array A.

Flowchart:–

Program:–

//Write a program to implement selection sort. // Date : 16/03/2010 #include #include void main() { int A[10]; int i,k,Small,Loc;

clrscr(); printf(“Enter Elements of Array:—\n”); for(i=0;i<=9;i++) scanf(“%d”,&A[i]); for(k=0;k<=9;k++) { Small=A[k]; Loc=k; for(i=k;i<=9;i++) if(Small>A[i]) { Small=A[i]; Loc=i; } A[Loc]=A[k]; A[k]=Small; } printf(“Sorted Array is:–\n\n”); for(i=0;i<=9;i++) printf(“%d “,A[i]); getch(); }

7.10 Write a program to implement Binary Search algorithm.

Algorithm:–

Step 1: Store 0 to Beg & 9 to End. Step 2: Compute Mid=(Beg+End)/2. Step 3: Read a Sorted Array Str & an Item to Search. Step 4: Repeat Step 5 to Step 8 while Item!=Str[Mid])&&(Beg<=End) otherwise go to Step 9 Step 5: Check ItemEnd go to Step 10 otherwise go to Step 11 Step 10: Display “Item Not Found” Step 11: Display “Item Found”

Flowchart:–

Program:–

//Write a program to implement Binary Search algorithm. // Date : 16/03/2010 #include #include void main() { int Str[10]; int i,Beg,End,Mid,Item; clrscr(); Beg=0; End=9; Mid=(Beg+End)/2; printf(“Enetr Any Sorted Array:–\n”); for(i=0;i<10;i++)

scanf(“%d”,&Str[i]); printf(“Enter Item Which U want to Search:–\n”); scanf(“%d”,&Item); while((Item!=Str[Mid])&&(Beg<=End)) { if(ItemEnd) printf(“Item Not Found\n”); else printf(“%d Found At Index %d\n”,Item,Mid); getch(); } 7.11 Write a program that will compute the length of a given character string.

Algorithm:–

Step 1: Read a string Str.

Step 2: For i=0 to End of String repeat Step 3 to Step Step 3: Compute Len=Len+1 Step 4: Display Len. Flowchart:–

Program:–

//Write a program that will compute the length of a given character string. // Date : 16/03/2010 #include #include void main() { char Str[50]; int i,Len; clrscr(); Len=0; printf(“Enter a String:—\n”); scanf(“%[^\n]s”,&Str);

for(i=0;Str[i]!=”;i++) Len=Len+1; printf(“Length of String is %d”,Len); getch(); } 7.12 Write a program that will count the number occurrences of a specified character in a given line of text.

Algorithm:–

Step 1: Read a string Str & a Character CheckChar Step 2: Length of String is Len Step 3: For i=0 to Len repeat Step 4 to Step 5 Step 4: Check CheckChar==Str[i] go to Step 5 otherwise go to Step 3 Step 5: Count=Count+1 Step 6: Display Count

Flowchart:–

Program:–

//Write a program that will count the number occurrences of a specified character in a //

given line of text.

// Date : 16/03/2010 #include #include void main() { char Str[50],CheckChar; int i,Count,Len; clrscr(); Count=0; printf(“Enter a String:—\n”); scanf(“%[^\n]s”,&Str); Len=strlen(Str);

fflush(stdin); printf(“Enter a charatcer:–\n”); scanf(“%c”,&CheckChar); for(i=0;i<=Len;i++) if(CheckChar==Str[i]) Count=Count+1; printf(“Number of occurences of %c is %d”,CheckChar,Count); getch(); }

7.13 Write a program to read a matrix of size m*n and print its transpose.

Algorithm:–

Step 1: Read Row, Col & Matrix A

Step 2: Display A Step 3: For i=0 to Col repeat Step 4 to Step 5 otherwise go to Step 6 Step 4: For j=0 to Row repeat Step 5 otherwise go to Step 3 Step 5: Compute C[i][j]=A[j][i] Step 6: Display C

Flowchart:–

Program:–

//Write a program to read a matrix of size m*n and print its transpose. // Date : 16/03/2010

#include #include #define MAX 10 void main() { int A[MAX][MAX],C[MAX][MAX]; int Row,Col,i,j; clrscr(); printf(“Enter Number of Rows:–\n”); scanf(“%d”,&Row); printf(“Enter Number of Column:–\n”); scanf(“%d”,&Col); printf(“Enter Matrix:—\n”); for(i=0;i
printf(“\n”); } for(i=0;i
0-07-041183-2 The first part denotes the region, the second represents publisher, the third identifies the book and the fourth is the check digit. The check digit is computed as follows:

Sum= (1*first digit) + (2*second digit) + (3*third digit)+…………….+ (9*ninth digit)

Check digit is the remainder when Sum is divided by 11. Write a program that reads a given ISBN number and check whether it represents a valid ISBN.

Algorithm:– Step 1: Read Array ISBN. Step 2: Compute Sum=Sum+(i*ISBN[i]) for i=0 to 9 Step 3: Compute CheckDig=Sum%11 Step 4: Check CheckDig=ISBN[10] then go to Step 5 Otherwise go to Step 6 Step 5: Display “Valid ISBN” Step 6: Display “Invalid ISBN”

Flowchart:–

Program:–

//Write a program that reads a given ISBN number and check whether it represents a valid ISBN. // Date : 16/03/2010 #include #include #define MAX 10 void main() { int ISBN[11]; int i,j,Sum,CheckDig; clrscr(); Sum=0; printf(“Enter ISBN Number:—\n”);

for(i=1;i<=10;i++) scanf(“%d”,&ISBN[i]); for(i=1;i<=9;i++) Sum=Sum+(i*ISBN[i]); CheckDig=Sum%11; if(CheckDig==ISBN[10]) printf(“\nValid ISBN\n”); else printf(“\nInvalid ISBN\n”); getch(); }

7.15 Write a program to read two matrices A and B and print the following:

a)

A + B and

b)

A – B.

Algorithm:–

Step 1: Read Row, Col, Array A & B.

Step 2: Display Array A & B. Step 3: Compute Addition of Array A & B & Store in Array C. Step 4: Display Array C

Flowchart:–

Program:– //Write a program to read two matrices A and B and print the following: //a)

A + B and

//b)

A – B.

// Date : 16/03/2010

#include #include #define MAX 10 void main() { int A[MAX][MAX],B[MAX][MAX],C[MAX][MAX]; int Row,Col,i,j; clrscr(); printf(“Enter Number of Rows:–\n”); scanf(“%d”,&Row); printf(“Enter Number of Column:–\n”); scanf(“%d”,&Col); printf(“Enter First Matrix:—\n”); for(i=0;i
for(i=0;i
} for(i=0;i
//Write a program that reads a given ISBN number and check whether it represents a valid ISBN. // Date : 16/03/2010 #include #include #define MAX 10 void main() { int ISBN[11]; int i,j,Sum,CheckDig; clrscr(); Sum=0; printf(“Enter ISBN Number:—\n”); for(i=1;i<=10;i++) scanf(“%d”,&ISBN[i]); for(i=1;i<=9;i++) Sum=Sum+(i*ISBN[i]); CheckDig=Sum%11; if(CheckDig==ISBN[10]) printf(“\nValid ISBN\n”); else printf(“\nInvalid ISBN\n”);

getch(); } 7.15 Write a program to read two matrices A and B and print the following: a) A + B and b) A – B. Program:– //Write a program to read two matrices A and B and print the following: //a) A + B and //b) A – B. // Date : 16/03/2010 #include #include #define MAX 10 void main() { int A[MAX][MAX],B[MAX][MAX],C[MAX][MAX]; int Row,Col,i,j; clrscr(); printf(“Enter Number of Rows:–\n”); scanf(“%d”,&Row); printf(“Enter Number of Column:–\n”); scanf(“%d”,&Col);

printf(“Enter First Matrix:—\n”); for(i=0;i
for(i=0;i
CHAPTER-8 8.3 Write a program to extract a portion of a character string and print the extracted string. Assume that m characters are extracted, starting with the nth character. Answer:

//Write a program to extract a portion of a character string and print the extracted string. //Assume that m characters are extracted, starting with the nth character. //Date: 18/03/2010#include #include #define MAX 50 void main() { char Str1[MAX]; int i,m,n,j;

clrscr(); printf("Enter A String:--\n"); scanf("%[^\n]s",Str1); printf("\nEnter Number of Characters Which U Wnat to Extract-->\n"); scanf("%d",&m); printf("\nEnter Beginnig Index from Which U Want to Extract-->\n"); scanf("%d",&n); printf("\nExtracted String is:--\n\n"); for(i=n-1;i

getch(); }

8.7 A Maruti car dealer maintains a reecord of sales of various vehicles in the following form:

Vehicle Type

Month of sales

Price

MARUTI-800 02/01

210000 MARUTI-DX

07/01

265000 GYPSY

04/02

MARUTI-VAN

08/02

315750

240000

Write a program to read this data into a table of strings and output the details of a particular vehicle sold during a specified period. The program should request the user to input the vehicle type and the period (starting month, ending month).

Answer: #include #include #define MAX 10 void main() { char Veh[MAX][MAX]={“”}; char Vehicle[MAX]; int St_Mon[MAX],En_Mon[MAX],StMon,EnMon;

long int Price[MAX]; int n,i; clrscr(); printf(“How Entries U Want to Enter\n”); scanf(“%d”,&n); printf(“Enter Vehcle Type,Starting Month, Ending Month & Price:–\n”); for(i=0;i
Month of Sales

Price\n”);

for(i=0;i
printf(“Enter the Starting & Ending Month\n”); scanf(“%d %d”,&StMon,&EnMon); for(i=0;i=StMon) { if(En_Mon[i]<=EnMon) { printf(“Vehicle Type %s is Sold During Period 0%d/0%d\n”,Vehicle,StMon,EnMon); getch(); exit(0); } } } } printf(“Vehicle Type %s Not Sold During Period 0%d/0%d\n”,Vehicle,StMon,EnMon); getch(); }

8.9 Write a program that reads the cost of an item in the form RRRR.PP (where RRRR denotes Rupees and PP denotes Paise) and converts the value to a string of words that express the numeric value in words. For example, if we input 125.75 the ouput should be“ONE HUNDRED TWENTY FIVE AND PAISE SEVENTY FIVE”.

Answer:

#include #include void main() { float Cost,Pai,Re,j; int Rup,i,R; clrscr(); printf("\nEnter Cost of an ITEM-->\n"); scanf("%f",&Cost); Rup = Cost; Pai = (Cost - Rup)*100; i=Rup/100; switch(i)

{ case 1: printf("ONE HUNDRED "); break; case 2: printf("TWO HUNDRED "); break; case 3: printf("THREE HUNDRED "); break; case 4: printf("FOUR HUNDRED "); break; case 5: printf("FIVE HUNDRED "); break; case 6: printf("SIX HUNDRED "); break; case 7: printf("SEVEN HUNDRED "); break; case 8: printf("EIGHT HUNDRED "); break; case 9: printf("NINE HUNDRED "); break; } i=Rup%100; R=i/10; Re=(float)i/10; switch(R) { case 1: printf("TEN"); break; case 2: printf("TWENTY "); break;

case 3: printf("THIRTY "); break; case 4: printf("FOURTY "); break; case 5: printf("FIFTY "); break; case 6: printf("SIXTY "); break; case 7: printf("SEVENTY "); break; case 8: printf("EIGHTY "); break; case 9: printf("NINETY "); break; } R=(Re-R)*10; switch(R) { case 1: printf("ONE"); break; case 2: printf("TWO "); break; case 3: printf("THREE "); break; case 4: printf("FOUR "); break; case 5: printf("FIVE "); break; case 6: printf("SIX "); break; case 7: printf("SEVEN "); break;

case 8: printf("EIGHT "); break; case 9: printf("NINE "); break; } printf("AND PAISE "); i=Pai/10; Re=(float)Pai/10; R=(Re-i)*10; switch(i) { case 1: printf("TEN"); break; case 2: printf("TWENTY "); break; case 3: printf("THIRTY "); break; case 4: printf("FOURTY "); break; case 5: printf("FIFTY "); break; case 6: printf("SIXTY "); break; case 7: printf("SEVENTY "); break; case 8: printf("EIGHTY "); break; case 9: printf("NINETY "); break;

} switch(R) { case 1: printf("ONE"); break; case 2: printf("TWO "); break; case 3: printf("THREE "); break; case 4: printf("FOUR "); break; case 5: printf("FIVE "); break; case 6: printf("SIX "); break; case 7: printf("SEVEN "); break; case 8: printf("EIGHT "); break; case 9: printf("NINE "); break; } getch(); }

8.10 Develop a program that will read and store the details of a list of students in the format

Roll No.

Name

Marks Obtained

………….

………

………………..

………….

………

………………..

And produce the following output lists: a)

Alphabetical list of names, roll numbers and marks obtained.

b)

List sorted on roll numbers.

c)

List sorted on marks (rank-wise list)

Answer:

#include #include #define MAX 50 void main() {

char Stu_Name[MAX][MAX]={“”}; //char Stu_Name1[MAX][MAX]={“”}; char Temp[MAX]=”"; int roll_No[MAX],Marks[MAX],n,i,In[MAX],Roll_No1[MAX],Marks1[MAX]; int Temp1,Temp2; int j; clrscr(); printf(“How Many Student Name U Want to Enter\n\n”); scanf(“%d”,&n); printf(“Enter Roll No. & Students Name & Total Marks:–\n”); for(i=0;i
Name

Marks\n”);

for(i=0;i
for(i=0;i0) { strcpy(Temp,Stu_Name[j]); strcpy(Stu_Name[j],Stu_Name[j+1]); strcpy(Stu_Name[j+1],Temp); Temp1=Roll_No[j]; Roll_No[j]=Roll_No[j+1]; Roll_No[j+1]=Temp1; Temp2=Marks[j]; Marks[j]=Marks[j+1]; Marks[j+1]=Temp2; } } } printf(“\nAccording to Student Names:–\n”); printf(“Roll No for(i=0;i
Name

Marks\n”);

printf(“%d

%s

%d\n”,Roll_No[i],Stu_Name[i],Marks[i]);

} for(i=0;iRoll_No[j+1]) { strcpy(Temp,Stu_Name[j]); strcpy(Stu_Name[j],Stu_Name[j+1]); strcpy(Stu_Name[j+1],Temp); Temp1=Roll_No[j]; Roll_No[j]=Roll_No[j+1]; Roll_No[j+1]=Temp1; Temp2=Marks[j]; Marks[j]=Marks[j+1]; Marks[j+1]=Temp2; } } } printf(“\nAccording to Marks:–\n”); printf(“Roll No

Name

Marks\n”);

for(i=0;i
%s


} for(i=0;i
printf(“\nAccording to Roll No:–\n”); printf(“Roll No

Name

Marks\n”);

for(i=0;i
%s


} getch(); }

8.11 Write a program to read to strings and compare them using the function strcmp() and print a mesaage that the first string is equal, less or greater than the second one.

Answer: #include #include #define MAX 50 void main() { char Str1[MAX],Str2[MAX];

clrscr();

printf(“Enter First String:–\n”); scanf(“%[^\n]s”,Str1);

fflush(stdin);

printf(“Enter Second String:–\n”); scanf(“%[^\n]s”,Str2);

if(strcmp(Str1,Str2)==0) printf(“\nBoth Strings are Equal\n”); else if(strcmp(Str1,Str2)<0) printf(“\nFirst String is Less Than\n”); else printf(“\nFirst String is Greater Than\n”); getch(); }

8.12 Write a program to read a line of text from the keyboard and print out the number of occurrences of a given substring using the function strstr(). Answer:

#include #include

#define MAX 50

void main() { char *Str1,*Str2,*Str3; int i,Len,Len1,Count;

clrscr();

Count=0;

printf(“Enter Text:–\n”); scanf(“%[^\n]s”,Str1);

fflush(stdin);

printf(“Enter Substring:–\n”); scanf(“%[^\n]s”,Str2);

Len=strlen(Str1); Len1=strlen(Str2);

strcpy(Str3,Str1);

for(i=0;i
printf(“\n\nNumber of occurences is:– %d”,Count); getch(); }

8.13 Write a program that will copy m consecutive characters from a string s1 beginning at position n into another string s2.

Answer: #include #include

#define MAX 50

void main() { char Str1[MAX],Str2[MAX]; int i,m,n,j;

clrscr();

printf(“Enter A String:–\n”); scanf(“%[^\n]s”,Str1);

printf(“\nEnter Number of Characters Which U Wnat to Copy–>\n”); scanf(“%d”,&m);

printf(“\nEnter Beginnig Index from Which U Want to Copy–>\n”); scanf(“%d”,&n);

for(i=n-1,j=0;i
Str2[m]=”;

printf(“\n\nCopied String is–> %s \n\n”,Str2); getch(); }

8.14 Write a program to create a directory of students with roll numbers.The program should display the roll number for a specified name and vice-versa.

Answer: #include #include

#define MAX 50 void main()

{ char Stu_Name[MAX][MAX],Name[MAX]; int Roll_No[MAX],n,i,Roll,Index;

clrscr();

printf(“How Many Student Name U Want to Enter\n\n”); scanf(“%d”,&n);

printf(“Enter Roll No. & Students Name:–\n”);

for(i=0;i
printf(“\nEnter Student Roll No which U want to Search:–\n”); scanf(“%d”,&Roll);

for(i=0;i
if(Roll==Roll_No[i]) { Index=i; } }

printf(“\nName of Student is –> %s whose Roll No is:– %d”,Stu_Name[Index],Roll);

printf(“\n\nEnter Student Name which U want to Search:–\n”); scanf(“%s”,Name);

for(i=0;i
printf(“\n\nRoll No of is:– %d Student Whose Name is:– %s\n”,Roll_No[Index],Stu_Name[Index]); getch();

}

8.15 Given a string char str[ ] =”123456789”; Write a program that displays the following: 1 232 34543 4567654 567898765

answer: #include #include

void main() { char Str[]=”123456789″; int i,j,k,l; clrscr();

for(i=0;i<5;i++) { for(k=4;k>i;k–) { printf(” “); } for(j=0,l=i;j<=i;j++,l++) { printf(“%c”,Str[l]); } l=l-2; for(k=0;k
}

Solution of C Programming by E Balaguruswamy

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