7 Reinforced Concrete By Peter W. Somers, S.E. Originally developed by Finley A. Charney, PhD, P.E.
Disclaimer Instru ctio nal Materials Complementi ng FEMA P-10 P-1051, 51, Design Examples
Reinforced Re inforced Concrete - 1
Top opic ic Overvi vervie ew
• • •
Concr on cre ete and re r einfo in forc rce ement behavi behavior or Reference stand s tanda ards rd s Requir qu ire ements by Seismi is mic c Design si gn Category
– Moment resisting frames – Shear walls
• •
Other topic s Design si gn Examples xamp les
Instru ctio nal Materials Complementi ng FEMA P-105 P-1051, 1, Design Examples
Reinforced Re inforced Concrete - 2
Top opic ic Overvi vervie ew
• • •
Concr on cre ete and re r einfo in forc rce ement behavi behavior or Reference stand s tanda ards rd s Requir qu ire ements by Seismi is mic c Design si gn Category
– Moment resisting frames – Shear walls
• •
Other topic s Design si gn Examples xamp les
Instru ctio nal Materials Complementi ng FEMA P-105 P-1051, 1, Design Examples
Reinforced Re inforced Concrete - 2
Top opic ic Overvi vervie ew
• • •
Concr on cre ete and re r einfo in forc rce ement behavi behavior or Reference stand s tanda ard rds s Requ quir ire ements by Seis ismi mic c Desi sign gn Category
– Moment resisting frames – Shear walls
• •
Other topics topic s Desi sign gn Examp xamples les
Instru ctio nal Materials Complementi ng FEMA P-105 P-1051, 1, Design Examples
Reinforced Re inforced Concrete - 3
Sum ummary mary of o f Con Concr cre ete Be Behavio havior r
•
Compre omp ressi ssive ve Ductili uct ility ty
– Strong in compression but brittle – Confinement improves ductility by • Maintaining concrete core integrity • Preventing longitudinal bar buckling
•
Flexur lexura al Ductili uct ility ty
– Longitudinal steel provides monotonic ductility at low reinforcement ratios
– Transverse steel needed to maintain ductility through reverse cycles and at very high strains (hinge development)
Instru ctio nal Materials Complementi ng FEMA P-105 P-1051, 1, Design Examples
Reinforced Re inforced Concrete - 4
Topic Overview
• • •
Concrete and reinforcement behavior Reference standards Requirements by Seismic Design Category
– Moment resisting frames – Shear walls
• •
Other topics Design Examples
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
Reinforced Concrete - 5
Reference Standards 16
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
Reinforced Concrete - 6
Modifications to Reference Standards
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Con onte text xt in
NEHRP Recommended Provisions
Provisions
A SCE 7-16
A CI 318-14
ASCE A SCE 7-16 fo f o r Con Co n c r ete et e St r u c t u r al d es i g n c r i t er i a:
Ch ap . 12
St r u c t u r al an al y s i s p r o c ed u r es :
Ch ap . 12
Des i g n o f c o n c r et e s t r u c t u r es :
Sec . 14.2
Provisi rov isions ons modifi mod ifica catio tions ns to ASC ASCE 77-10 ASCE A SCE 7-16 mo m o d i f i c ati at i o n s t o A CI 318-14
Instru ctio nal Materials Complementi ng FEMA P-105 P-1051, 1, Design Examples
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Ref er en c e St an d ar d s ASCE A SCE 7-16: Define fin es syst s yste ems and classification classif ications s Provides rov ides desig design n coe co efficients ffi cients ACI A CI 318-14: Provides rov ides system sy stem desig design n and and deta detaili iling ng require requir ements cons co nsis istent tent wit w ith h AS A SCE 7-16 syst sy ste em crite cri teria ria Modif od ifii ed by ASCE ASCE 77-16
Instru ctio nal Materials Complementi ng FEMA P-105 P-1051, 1, Design Examples
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Us e o f Ref er en c e St an d ar d s
• ACI A CI 318 – Chapter 18, Earthquake-Resistant Earthquake-Resistant Structures
• ASCE A SCE 7-16 and an d Pro Pr o v i s i o n s Sect Sec t i o n 14.2 – Modifications to ACI 318 – Detailing requirements for concrete piles ASCE 7-1 7-10 0 • Provisions s u p er s ed e ASCE modifications
Instru ctio nal Materials Complementi ng FEMA P-105 P-1051, 1, Design Examples
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Det ai led Mod Modif ific ica ati tion ons s to t o AC A CI 318 pi ers and wall se s egme gm ents nt s • Wall pie • Membe mb ers not no t de d esign si gna ated as as part of o f the t he LRF LRFS walls • Columns supporting discontinuous walls nt erme rm edia di ate pre pr ecast walls • Inte • Plain lain concrete con crete struct str uctures ures A n c h o r i n g t o c o n c r ete et e • An • Foundations • Ac A c c ept ep t anc an c e cr c r i t eri er i a fo f o r v ali al i d ati at i o n t est es t i n g o f spe sp ecia ci al pre pr ecast walls
Instru ctio nal Materials Complementi ng FEMA P-105 P-1051, 1, Design Examples
Reinforced Re inforced Concrete - 11
Topic Overview
• • •
Concrete and reinforcement behavior Reference standards Requirements by Seismic Design Category
– Moment resisting frames – Shear walls
• •
Other topics Design Examples
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Design Coefficients Moment Resisting Frames Seismic Force Resisting System Special R/C Moment Frame Intermediate R/C Moment Frame Ordinary R/C Moment Frame
Deflection
Response Modification Coefficient, R
Amplification
8
5.5
5
4.5
3
2.5
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
Factor, Cd
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Performance Objectives
•
Special Moment Frames
– Strong column • Avoid story mechanism
– Hinge development • Confined concrete core • Prevent rebar buckling • Prevent shear failure
– Member shear strength – Joint shear strength – Rebar development and splices (confined)
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Performance Objectives
•
Intermediate Moment Frames
– Avoid shear failures in beams and columns – Plastic hinge development in beams and columns – Toughness requirements for two-way slabs without beams
•
Ordinary Moment Frames
– Minimum ductility and toughness – Continuous top and bottom beam reinforcement – Minimum column shear failure protection
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Summary of Seismic Detailing for Frames Issue
Ordinary
Intermediate
Special
Hinge development and confinement
minor
full
Bar buckling
lesser
full
Member shear
lesser
full
minor
full
Joint shear
minor
Strong column
full
Rebar development
lesser
lesser
full
Load reversal
minor
lesser
full
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Special Moment Frames
• • • • •
General detailing requirements Beams Joints Columns Example problem
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Frame Mechanisms “ strong column – weak beam”
Story mechanism
Sway mechanism
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Required Column Strength M nc1
M nb1
M
nc
1.2 Mnb
M nb2
M nc2
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Hinge Development
•
Tightly Spaced Hoops
– Provide confinement to increase concrete strength and usable compressive strain
– Provide lateral support to compression bars to prevent buckling
– Act as shear reinforcement and preclude shear failures
– Control splitting cracks from high bar bond stresses
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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ACI 318, Overview of SMF: Beam Longitudinal Reinforcement 200
f y
0.025
At least 2 bars continuous top & bottom Joint face Mn+ not less than 50% MnMin. Mn+ or Mn- not less than 25% max. Mn at joint face Splice away from hinges and enclose within hoops or spirals
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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ACI 318, Overview of SMF: Beam Transverse Reinforcement Closed hoops at hinging regions with “seismic” hook 135º hook, 6dh 3” extension Maximum spacing of hoops: d/4
6db
6”
Longitudinal bars on perimeter tied as if column bars 2h min
Stirrups elsewhere, s
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
d/2
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ACI 318, Overview of SMF: Beam Shear Strength 1.2D + 1.0L + 0.2S
Mpr1
Mpr2
n
Ve1
Ve
Ve2
Mpr 1 Mpr 2 n
If earthquake-induced shear force
w u n 2
Ve
Mpr Mn f s
with
1.25f y , 1.0
by analysis
1V e 2
and Pu
' g c
A f
then Vc = 0
20
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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ACI 318, Overview of SMF: Beam-Column Joint Vcol T
V j
T C Vcol
C
V j
T 1.25f y A s, top C 1.25f y A s, bottom
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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ACI 318, Overview of SMF: Beam-column Joint
20 Vn 15 f 'c A j 12 • • • •
Vn often controls size of columns Coefficient depends on joint confinement To reduce shear demand, increase beam depth Keep column stronger than beam
Instru ctio nal Materials Complementin g FEMA P-1051, Design Examp les
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ACI 318, Overview of SMF: Column Transverse Reinforcement at Potential Hinging Region hx
hx
14 h x so 4 3 Spacing shall not exceed the smallest of: b/4 or 6 db or so (4” to 6”) Distance between longitudinal bas supported by hoops or cross ties, hx 14” Instru ctio nal Materials Complementin g FEMA P-1051, Design Examples
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Topic Overview
• • •
Concrete and reinforcement behavior Reference standards Requirements by Seismic Design Category
– Moment resisting frames – Shear walls
• •
Other topics Design Examples
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
Reinforced Concrete - 27
Design Coefficients Structural Walls (Bearing Systems) Seismic Force Resisting System
Special R/C Struc tural Walls Ordinary R/C Structural Walls Intermediate Precast
Response
Deflection
Modification
Amplification
Coefficient, R
Factor, Cd
5
5
4
4
4
4
3
3
Structural Walls
Ordinary Precast Walls
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Performance Objectives
•
Special R/C structural walls
– Resist axial forces, flexure and shear – Boundary members • Where compression stress/strain is large, maintain capacity
– Development of rebar in panel – Ductile coupling beams
•
Ordinary R/C structural walls
– No seismic requirements, Ch. 18 does not apply
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Design Philosophy
•
Flexural yielding will occur in predetermined flexural hinging regions
•
Brittle failure mechanisms will be precluded
– Diagonal tension – Sliding hinges – Local buckling – Shear failures in coupling beams
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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ACI 318, Overview of Special Walls: General Requirements w
t = parallel to shear plane hw
= perpendicular to shear plane Shear plane, Acv = web thickness x length of wall
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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ACI 318, Overview of Special Walls: General Requirements
•
and
t
not less than 0.0025 unless
V u
Acv
f 'c
then per Sec.11.6
• •
Spacing not to exceed 18 in. Reinforcement contributing to Vn shall be continuous and distributed across the shear plane
Instru ctio nal Materials Complementin g FEMA P-1051, Design Examp les
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ACI 318, Overview of Special Walls: General Requirements
•
Two curtains of reinforcing required if:
V u •
2 Acv
f 'c
Design shear force determined from lateral load analysis
Instru ctio nal Materials Complementin g FEMA P-1051, Design Examp les
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ACI 318, Overview of Special Walls: General Requirements
•
Shear strength:
V n
Acv c
f 'c
t f y
c = 3.0 for hw/ w1.5 c = 2.0 for hw/ w2.0 Linear interpolation between
•
Walls must have reinforcement in two orthogonal directions
Instru ctio nal Materials Complementin g FEMA P-1051, Design Examp les
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ACI 318, Overview of Special Walls: General Requirements
•
For axial load and flexure, design like a column to determine axial load – moment interaction P M
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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ACI 318, Overview of Special Walls: Boundary Elements For walls with a high compression demand at the edges – special boundary elements are required
Widened end with confinement Extra confinement and/or longitudinal bars at end Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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ACI 318: Overview of Special Walls Boundary Elements Two options for determining need for boundary elements
•
Strain-based: Determined using wall deflection and associated wall curvature
•
Stress-based: Determined using maximum extreme fiber compressive
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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ACI 318, Overview of Special Walls: Boundary Elements—Strain
•
Boundary elements are required if: c
w
1.5 u 600
hw
= Design displacement = Depth to neutral axis from strain compatibility analysis with loads causing u
u
c
Instru ctio nal Materials Complementin g FEMA P-1051, Design Examp les
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ACI 318, Overview of Walls: Boundary Elements—Strain
•
Where required, boundary elements must extend up the wall from the critical section a distance not less than the larger of:
w
or
Mu /4Vu
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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ACI 318: Overview of Walls Boundary Elements—Stress
•
Boundary elements are required where the maximum extreme fiber compressive stress calculated based on factored load effects, linear elastic concrete behavior and gross section properties, exceeds 0.2f’ c
•
Boundary element can be discontinued where the compressive stress is less than 0.15f’ c
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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ACI 318: Overview of Walls Boundary Elements—Detailing •
Boundary elements must extend horizontally not less than the larger of c /2 or c -0.1 w
• •
Width of boundary elements, b > h u /16 or 12”
•
Transverse reinforcement must extend into the foundation
•
Horizontal reinforcement shall extend into the core of boundary and anchored to develop fy.
In flanged walls, boundary element must include all of the effective flange width and at least 12 in. of the web
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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ACI 318: Overview of Walls Coupling Beams Requirements based on aspect ratio and shear demand n
/h 4
n
/ h 2 and V u
Design as Special Moment Frame beam
Other cases
4
f 'c Acw
Reinforce with 2 intersecting groups of diagonal bars Standard or diagonal
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Topic Overview
• • •
Concrete and reinforcement behavior Reference standards Requirements by Seismic Design Category
– Moment resisting frames – Shear walls
• •
Other topics Design Examples
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Members Not Part of LFRS
•
In frame members not designated as part of the lateral-force-resisting system in regions of high seismic risk:
– Must be able to support gravity loads while subjected to the design displacement
– Transverse reinforcement increases depending on: Forces induced by drift Axial force in member
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Precast Concrete: Performance Objectives
Field connections at points of low stress
Field connections must yield
Strong connections
Ductile connections
•
•
Configure system so that hinges occur in factory cast members away from field splices
Inelastic action at field splice
Instru ctio nal Materials Complementin g FEMA P-1051, Design Examp les
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Topic Overview
• • •
Concrete and reinforcement behavior Reference standards Requirements by Seismic Design Category
– Moment resisting frames – Shear walls
• •
Other topics Design Examples from FEMA P-751
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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IK5
Special Moment Frame Example A
A’
B
C
C’
N
D 1
• Located in Berkeley, California • 12-story concrete building • N-S direction: SMF • E-W direction: dual system • Seismic Design Category D
2
’ 0 1 2 = ’ 0 3 @ 7
3 4 5 6
• Modal Analysis Procedure
7 5 @ 20’ = 100’
8
Typical Floor Plan Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Slide 47 IK5
Update required. Insung Kim, 8/4/2016
Frame Elevations
Grid Lines 3 to 6
Grid Lines 2 and 7
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Story Shears: E-W Loading
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Layout of Reinforcement #4 stirrup 4
#8 bar, assumed
” 5 . 8 2
” ” 5 . 2 9 3 2
24” 30” Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Design Strengths Design Aspect
Strength Used
Beam flexure
Design strength
Beam shear
Maximum probable strength
Beam-column joint
Maximum probable strength
Column flexure
1.2 times nominal beam strength
Column shear
Maximum probable strength
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Bending Moment Envelopes: Frame 1 Beams, 7th Floor
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Beam Reinforcement: Longitudinal Design for Negative Moment at the Face of the Interior Support (Grid A’): Mu = 1.46(-602) + 0.5(-278) + 1.0(-3,973) = -4,976 inch-kips One #7 bars in addition to the four #8 bars required for minimum steel: As = 4(0.79) + 1(0.60) = 3.76 in^2 a = 3.76 (60)/[0.85 (5) 24] = 2.21 inches Mn = 0.9(3.76)60(29.5 – 2.21/2) = 5,765 inch-kips > 4,976 inch-kips . Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Beam Reinforcement: Longitudinal (continued) Check additional requirements: Minimum of two bars continuous top and bottom:
OK (three #8 bars continuous top OK (four #8 bars continuous top and bottom)
Positive moment strength greater than 50 percent negative moment strength at a joint:
OK (at all joints)
Minimum strength along member greater than 0.25 maximum strength:
OK (As provided = four #8 bars is more than 25 percent of reinforcement provided at joints)
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Beam Reinforcement: Layout
1
4
4
Instru ctio nal Materials Complementin g FEMA P-1051, Design Examples
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Determine Beam Design Shear
B
Assumed hinging mechanism
C
6,841
Probable moment strength, Mpr (k-in) Vu,grav = 34.1 kips
7,929 20’ – 30” = 17’-6”=210”
V e
M pr 1 M pr 2 n
V u , grav
7,929 6,841 210
34.1 104.4 kips
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Loading
Beam Shear Force
Hinge locations A
A'
7,042
B
C 7,042
7,042
7,042
(a) Seismic moment (tension side) in.-kips
5,519
5,519
5,519
Beam moments
5,519
210" 15"
15"
240"
58.1
58.1
58.1 (b) Seismic shear positive
Seismic shear
kips 58.1
58.1
33.8
32.9
58.1
33.3
33.3
33.3
33.3
(c) Gravity shear (1.42 D + 0.5 L) positive kips
91.4
91.9 24.8
25.2
91.4 24.8 (d) Design shear seismic + gravity
24.3 91.0
91.4
Factored gravity shear
24.8
24.8 91.4
Design shear
positive kips
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Beam Reinforcement: Transverse Vseismic > 50% Vu therefore take Vc = 0
Use 4 legged #4 stirrups smax
Av f y d V e
0.75(0.8)(60)(29.5) 104.4
10.2 in.
At ends of beam s = 6 in. (near midspan, s = 6.0 in. w/ 2 legged stirrup)
Instru ctio nal Materials Complementin g FEMA P-1051, Design Examples
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Beam Reinforcement: Transverse
•
Check maximum spacing of hoops within plastic hinge length (2h)
– d/4 = 7.4 in. – 6db = 6.0 in. – 6 in. Therefore, 6.0 in. spacing at ends is adequate At beam rebar splices, s = 4.0 in.
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Joint Shear Force
V j
Vcol T
T C V col
C
T 1.25 f y As , top
V j
C 1.25 f y As , bottom But how to compute Vcol? Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Joint Shear Force V col
V col
M M V V h pr , R R L pr , L 2
h
lc
At 7th Floor, Column C:
V col
7,929 6,841 70.3 70.3 156
30 2
108.2 kips
V e,L
M pr,R
c
l
V e,R
M pr,L
V col
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Joint Shear Force 108 282
237
411
T 1.25 f y As ,top
282 kips C 1.25 f y As ,bot 237 kips V j T C V col 411 kips 15 f c' A j 15 5,000 (30) 2 955 V n 0.85 955 811 kips 411 kips
V n
Instru ctio nal Materials Complementin g FEMA P-1051, Design Examples
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Frame 1 Column Design Column:
then:
Pu
f 'c Ag
A
A'
10
M
nc
1.2 M nb
B
P L = 78 kips Includes P D = 367 kips level 7 " 2 3
" 0 ' 3 1
Level 7
30" " 2 3
Design column using standard P-M interaction curve
20'-0"
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
Level 6
20'-0"
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Column Design Moments Design for strong column based on nominal beam moment strengths
A
A'
B
6,406
Beam moments (Level 7)
M
5,498
nc
1.2 M nb
1.25,498 6,406 14,285 k - ft 7,142 7,142
Column moments (Level 7), assume uniform distribution top and bottom
Instru ctio nal Materials Complementin g FEMA P-1051, Design Examples
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Column Transverse Reinforcement
nl: number of longitudinal bars that are laterally supported by the corner of hoops or by seismic hooks
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Column Transverse Reinforcement Maximum spacing is smallest of: h/4 = 30/4 = 7.5 in. 6db = 6*1.0 = 6.0 in. (#8 bars) so calculated as follows: 14 h x so 4 3
for 12 #8 vertical bars and #4 hoops, hx = 8.33 in. and so = 5.72 in. Next, check confinement requirements……
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Column Transverse Reinforcement Assume 4 in. hoop spacing: f c' < 10,000 psi and Pu< 0.3 f c'Ag Equation (c) was not required. Ash
f 'c Ag (4)(27) 5 900 1 0.63 in 2 0.3 sbc 1 0 . 3 60 729 f yt Ach
and Ash
0.09sbc
f 'c f yt
5 0.09(4)(27) 0.81 in 2 60
Therefore, use #4 bar hoops with 4 legs Ash = 0.80 in2 Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Determine Column Shear Based on probable moment strength of columns and can be limited by probable moment strength of beams
Mpr,1
Mpr,2
Mpr,top Vseismic
n
Mpr,3
Mpr,4
Vseismic Mpr,bottom
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
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Column Shear Design Based on column moments: Mpr,col = 14,940 k-in (12 #8 vert and Pmax)
V e
2(14,940)
For Pmin
(124)
241 kips
f 'c Ag
20
5(30)(3) 20
225 kips,
Vc can be included in shear calculation
Instru ctio nal Materials Complementin g FEMA P-1051, Design Examples
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Column Shear Design Assume 6 in. max hoop spacing at mid-height of column
V c V s
2
f 'c bd 2 5,000 (30)(27.5) 117 kips
Av f y d
0.8(60)(27.5)
220 kips
s 6 V n (V c V s ) 0.75(117 220) 252 kips 241 kips OK
Hoops:
4 legs #4 s = 6 in. max
Instru ctio nal Materials Complementin g FEMA P-1051, Design Examples
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Column Reinforcement A'
•
Confinement length, l o , greater of:
• • •
Level 7 " 2 3 " 2
h = 30 in. Hc/6 = (156-32)/6 = 20.7 in.
" 4 t a
(12) #8 bars
7
#4 hoops +
+
" 0 3
" 6 t a 7
18 in.
30" " 4 t a 7
– Therefore, use 30 in.
" 2
" 2 3
Level 6
" 4 t a 7
" 2
30"
Instru ctio nal Materials Complementin g FEMA P-1051, Design Examp les
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Structural Wall Example A
• Same building as moment
A’
B
C
C’
1
frame example
• 12-story concrete building • N-S direction: SMF • E-W direction: dual system • Seismic Design Category D • Modal Analysis Procedure
N
D
2
’ 0 1 2 = ’ 0 3 @ 7
3 4 5 6 7
Shear wall @ grid 3-6
8
5 @ 20’ = 100’
Typical Floor Plan Instru ctio nal Materials Complementin g FEMA P-1051, Design Examp les
Reinforced Concrete - 72
Structural Wall
17’-6”=210”
16” 30” x 30” column
Shear wall cross section
Ag = (16)(210)+2(30)(30) = 5,160 sq in Acv = 16[(210)+2(30)] = 4,320 sq in
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
Reinforced Concrete - 73
Shear Panel Reinforcement V n
Acv
'
f c
t f y
Vu = 769 kips (below level 2)
l
Panel
to A cv
f’c = 5,000 psi, f y = 60 ksi α
= 2.0
= 0.6 (per ACI 9.3.4(a))
A cv
t
Req’d t = 0.0019 Min (and t) = 0.0025 Use #5 @ 12” o.c. each face: t= 0.0032 and Vn = 869 kips Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
Reinforced Concrete - 74
Axial-Flexural Design At ground floor: shear and moment determined from the lateral analysis and axial load from gravity load run down. All are factored forces.
• • •
Mu = 30,641 kip-ft Pu,max = 6,044 kips Pu,min = 2,460 kips
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
Reinforced Concrete - 75
Axial and Flexural Design P-M interaction Wall reinforcement: #5 @12” o.c. Boundary reinforcement: 12 #9 each end
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
Reinforced Concrete - 76
Boundary Element Check Use stress-based procedure (ACI 18.10.6.3). Boundary Elements required if max stress > 0.2 f’c Ground level axial load and moment are determined based on factored forces. Pu Ag
M u S
6,044 5,160
30,641(12) 284,444
2.46ksi 0.49 f c'
Need confined boundary element (extend up to below 9th floor where max stress <
Instru ctio nal Materials Complementin g FEMA P-1051, Design Examp les
0.15f’c) Reinforced Concrete - 77
Boundary Element Length Length = larger of c/2 or c-0.1Lw From P-M interaction, max c = 72.6 in. So, c/2 = 38.8 and c-0.1Lw = 50.6 in Since length > column dimension, either
• •
Extend boundary into wall panel Increase f’c = reduce boundary element length
For this example, assume f’c = 7,000 psi, Then req’d boundary element length is 28.7 in. Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
Reinforced Concrete - 78
Boundary Element Confinement Transverse reinforcement in boundary elements is to be designed essentially like column transverse reinforcement. Assume #5 ties and 4 in. spacing Ash
0 .09 sb c
'
f c
f y
7 0 .09 ( 4 )( 27 ) 1 . 13 in 2 60
#5 with 4 legs, Ash = 1.24 in2
Width of the flexural compression zone, b > 12in. or h u/16 Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
Reinforced Concrete - 79
Questions
Instru ctio nal Materials Complementi ng FEMA P-1051, Design Examples
Reinforced Concrete - 80