Kimia Saintek Sbmptn 2016

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PEMBAHASAN SBMPTN 2016 TKD SAINTEK PEMBAHASAN KIMIA (KODE NASKAH : 237) Pembahas : Yuli Nestiyarum,S.Pd & Vaishnavita Nawakusuma, S.Si.

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31. Jawaban : D Pembahasan : Energi ionisasi meningkat drastis pada energi pengionan keempat, maka A termasuk u golongan IV A ( +4) 32. Jawaban : C Pembahasan : A X2 E2 (Bentuk V)

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PEMBAHASAN SBMPTN 2016 TKD SAINTEK PEMBAHASAN KIMIA (KODE NASKAH : 237)

Documents

Pembahas : Yuli Nestiyarum,S.Pd & Vaishnavita Nawakusuma, S.Si.

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Massa N

=

Jumlah atom

=

-3

gram = 35 x 10  gram

= 1,505 x 10

21

34. Jawaban : B Pembahasan : K2 (Pt Cl4)

0,02 mol

+

2 NH3

(Pt ( NH3)2 Cl2)

0,02 mol (pereaksi pembatas)

X = 3 gram

+

2 KCl

35. Jawaban : D Pembahasan : 2H2S + 302

2H2O + 2X

1,5 L 1,5 L Sign up to vote on this title

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PEMBAHASAN SBMPTN 2016 TKD SAINTEK PEMBAHASAN KIMIA (KODE NASKAH : 237)

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Pembahas : Yuli Nestiyarum,S.Pd & Vaishnavita Nawakusuma, S.Si.

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36. Jawaban : D Pembahasan :

    2 H       

 H 

 H 

|

|

C 



C 

|

|

 H 

 H 

      H    7 O  O   4O  C   O   6( H   O  H )     

-3120 = kiri - kanan -3120 = 12360 360   2C   C   7490 490  8740 740  12460 460  (C-C) = 285 37. Jawaban : B Pembahasan : -

3 Cl2

5 Cl

0

-1

-

+

1 ClO3

+5

Red = 1(x5) oks = 5(x1) Sign up to vote on this title

 1 mol

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40. Jawaban : E Pembahasan : 2F2

+

O2

20F2

m r

1 2x

1 x

2x

s

1  – 2x

1-x

2x

0,5

0,75

0,5

= 0,1333 41. Jawaban : B Pembahasan : ∆Tf 1

Kf . m . I

= =

∆Tf 2

kf . m

2

0,5

1 Sign up to vote on this title

37

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42. Jawaban : C Pembahasan : FLASH METHODE H



 besar  kecil      kecil     800 x  100 100 x      x  100    

= Ka  -9

= 10

-9

= 7 x 10 pH = 9 - log 7 43. Jawaban : C Pembahasan :

Na HCO3 + NaH2PO4 Basa

Asam +

+H

 H2CO3 + Na2HPO4 Asam

konjugasi +

Basa

konjugasi

-H

44. Jawaban : E Pembahasan : 1. H3C  – CH = CH  – CH3 + Cl2

H3C  – CH  – CH  – CH3 Sign up to vote on this title

Cl 5. H C

 CH = CH  C H  + Cl

HC

Cl Useful

 CH  CH  C H

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